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Thread: [RESOLVED] Circular orbit!

  1. #1

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    Arabic Poster ComputerJy's Avatar
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    Resolved [RESOLVED] Circular orbit!

    Hi all...

    Does anybody know how to implement as circular orbit for a point (something to move in a circle)

    I've tried lots of methods depending on (cos , sin) but it ain't that good

    P.S. The language isn't a problem.. I know'em all
    "I'm not normally a praying man, but if you're up there, save me... Superman!" - Homer Simpson
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    Re: Circular orbit!

    Ok since the language is not a problem (you know'em all) my answer in greek:
    Allaxe se polikes syntetagmenes kai ayxise diadoxika ti gwnia theta apo mithen mehri dyo pi.
    "bla, bla,... exists number M so for each n > M bla, bla..." Exists? Where is it? (Kronecker said...)

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    Frenzied Member zaza's Avatar
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    Re: Circular orbit!

    Easiest way: do it in cylindrical polars. i.e. change your coordinate system to r and theta. Then just increment theta with each time step, or use the angular velocity to work out where you are around the orbit. Angular velocity is, as you might expect, 2Pi/T where T is the period of rotation (using radians).

    If you must do it in cartesians, then X = r cos theta, Y = r sin theta.


    zaza

  4. #4

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    Re: Circular orbit!

    Quote Originally Posted by zaza
    Easiest way: do it in cylindrical polars. i.e. change your coordinate system to r and theta. Then just increment theta with each time step, or use the angular velocity to work out where you are around the orbit. Angular velocity is, as you might expect, 2Pi/T where T is the period of rotation (using radians).

    If you must do it in cartesians, then X = r cos theta, Y = r sin theta.


    zaza
    I've been doing it this way but I didn't realise this until you explained it to me
    Thank you very much!
    "I'm not normally a praying man, but if you're up there, save me... Superman!" - Homer Simpson
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    Talking Re: Circular orbit!

    Quote Originally Posted by zaza
    Easiest way: do it in cylindrical polars. i.e. change your coordinate system to r and theta. Then just increment theta with each time step,
    Exactly what i suggested in greek
    "bla, bla,... exists number M so for each n > M bla, bla..." Exists? Where is it? (Kronecker said...)

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