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Thread: Boole's Inequality

  1. #1

    Thread Starter
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    Feb 2006
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    Boole's Inequality

    Hi all,

    I was just wondering if anyone knew the proof for boole's inequality

    That is P(A1 U A2 U A3 U ... U Ai)<P(A1 + A2 + A3 + .. + Ai)

    where u is the union

    Thanks

  2. #2
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    Nov 2005
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    Re: Boole's Inequality

    if you mean P(A1 U A2 U...U Ai) <= P(A1) + P(A2) +...+P(Ai)
    for n = 2: P(A1 U A2) = P(A1) + P(A2) - P(A ^ B) <= P(A1) + P(A2)
    Suppose it holds for n = k. We must proove it for n = k + 1
    P(A1 U A2 U...U Ak U Ak+1) = P(UA1..k U Ak+1) <= P(UA1..k) + P(Ak+1) <= P(A1) + P(A2) +...+ P(Ak) + P(Ak+1)
    "bla, bla,... exists number M so for each n > M bla, bla..." Exists? Where is it? (Kronecker said...)

  3. #3

    Thread Starter
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    Re: Boole's Inequality

    Thanks a lot

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