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Feb 1st, 2001, 10:46 AM
#1
Thread Starter
New Member
How do you reverse the calculation imposed by a modulus symbol? ie if you encrypt by (number + 7) Mod 10 in an encryption program, how could one write a separate decryption program that accepts an encrypted number and decrypts it back to its original state?
Additionally - how could one code a program that reads in a 1-5 digit integer in a singular textbox then total and print the amount of number 7's typed into the text box?
please help
F
[email protected]
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Feb 1st, 2001, 03:37 PM
#2
Frenzied Member
Mid Function.
Put data from text box into a string and use Mid Function in a For loop to examine the individual digits.
It is not clear what you mean by (Number + 7) Mod ten. Is the Mod function applied to each digit of a long decimal number? Is it applied to byte data?
Live long & prosper.
The Dinosaur from prehistoric era prior to computers.
Eschew obfuscation!
If a billion people believe a foolish idea, it is still a foolish idea!
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Feb 2nd, 2001, 07:33 AM
#3
transcendental analytic
Code:
'limits textbox to 5 characters
Private Sub Text1_Change()
If Len(Text1) > 5 Then Text1 = Left(Text1, 5)
End Sub
'count 7'ns in a tetbox
a=instr(text1,"7")
Do while a
count=count+1
a=instr(a+1,text1,"7")
loop
Using mod for a encryption isn't a too bright idea, you have to be sure to have an individual result for each number, otherways you can't decrypt it, if you pass a number trough (number+7) mod 10 number has to be a integer from X to X+9.
Use  
writing software in C++ is like driving rivets into steel beam with a toothpick.
writing haskell makes your life easier:
reverse (p (6*9)) where p x|x==0=""|True=chr (48+z): p y where (y,z)=divMod x 13
To throw away OOP for low level languages is myopia, to keep OOP is hyperopia. To throw away OOP for a high level language is insight.
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