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Thread: Probability distribution with horses

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    Addicted Member Rassis's Avatar
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    Jun 2004
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    Re: Probability distribution with horses

    If you compare each horse with the most probable winner (horse 6), you get the following chances that they can win the race (or that the horse 6 looses to each one of the other horses):

    Horse 1: P[N((59.50-57.00);sqrt(0.5^2+0.5^2)) < 0 = 0.000230
    Horse 2: P[N((59.50-57.20);sqrt(0.5^2+0.5^2)) < 0 = 0.000572
    Horse 3: P[N((59.50-57.35);sqrt(0.5^2+0.5^2)) < 0 = 0.001181
    Horse 4: P[N((59.50-57.80);sqrt(0.5^2+0.5^2)) < 0 = 0.008105
    Horse 5: P[N((59.50-58.10);sqrt(0.5^2+0.5^2)) < 0 = 0.023857
    Last edited by Rassis; Sep 1st, 2005 at 05:13 AM.
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