help with an equation

[Sandsy]

I cant do this equation and I really need help, I need to transpose this equation to make the subject b

... pleeeease help!

sigma = f/(b*h) + (6*M)/(b*h^2)

There's got to be someone out there that can do this.

Thanks, Sandsy.

[zaza]

Hi,

If you really mean the equation that you posted, then I can't believe you cannot rearrange for b, unless this is your first ever experience of algebra.

b = f/(sigma x h) + 6M/(sigma x h^2)

If, however, you mean the following:

sigma = f/bh + 6M/(bh)^2

then just multiply through by (bh)^2 and collect on one side:

sigma x h^2 x b^2 - fh x b - 6M = 0

It's a quadratic in b and you can solve in the usual way:

b = (f +- sqrt(f^2 + 24M x sigma))/(2h x sigma)


zaza

[taxes]

Hi,

It's only a quadratic if you decide to make it one!!

There are several ways to isolate B and zaza's post should give you the clues. But he is right, it is not a difficult equation

[peaches_2479]

hey i joined to get someonr to help me as i'm doing as maths this year and everyone is putting me off by saying it's really hard
anyway i need some help with completeing this square

y2(squared)+3y+2=0 and 3x(squared)+13x-10=0


thanks

[taxes]

Hi Peaches,

What's that got to do with VB.NET???????

Do a google search on "Completing the Square" and you will find lots of help.

[krtxmrtz]

b = (f +- sqrt(f^2 + 24M x sigma))/(2h x sigma)
zaza

Hi zaza, I think it's much much easier! Notice both terms on the right side have b in the denominator (not b squared!) so you just multiply both sides by b/sigma and get

b = f/(sigma*h) + (6*M)/(sigma*h^2)

[taxes]

Hi zaza, I think it's much much easier! Notice both terms on the right side have b in the denominator (not b squared!) so you just multiply both sides by b/sigma and get

b = f/(sigma*h) + (6*M)/(sigma*h^2)

Which is EXACTLY what zaza first posted

[krtxmrtz]

Which is EXACTLY what zaza first posted

Yep!!!! My apologies to zaza for having skipped all the lines of his post but the final result...