Having trouble displaying variables. [SOLVED]

[machinist]

Basically i store their username when they log in and want their control panel to say Hello welcome back [username goes here].

But for some reason i can't get it to work.
This is the code i am using.
(To see if the have logged in i use a variable).

<?
If ($_SESSION[login]=1){
print($_SESSION[user]);
} else {
echo 'Not logged in';
}
?>

Before you ask me to check the variable, if i use this code it returns the message (Welcome back Scott).

<?
If ($_SESSION[user]=Scott){
print('Welcome back Scott');
} else {
echo 'Not logged in as Scott';
}
?>

Any help would be appreciated.

[visualAd]

If you are doing a comparision you need to use the "==" operator. In PHP, = is the assignment operator.

The following will always evaluate to true and execute the echo statement because $var = 1 assigns 1 to the variable $var beforethe if statment is evaluated.

$var = 0;

if ($var = 1)
{
    echo 'TRUE';
} 

The correct way is as follows:

$var = 0;

if ($var == 1)
{
    echo 'TRUE';
} 

[machinist]

Ok thanks. So it is a bit like C++ then.

[sciguyryan]

Ok thanks. So it is a bit like C++ then.

Yes, PHP is based on C I think

It has a lot in common with C (And a lot different too)

Have a look here, this is the PHP homepage
http://www.php.net/manual/en/tutorial.php

And remember if your thread has been solved, edit your original post and add Resolved to the title and a green checkmark as its icon so others know this thread is solved

Cheers,

RyanJ