problem with mixing php with html

[SeeThroughGuy]

Hey, I got a problem with mixing php with html, the code is like this:

<form action="/vote.php?<?=$id?>&vote=true">

Its like a voting system Ive got on vote.php and redirect back to vote.php when you vote and enters the information into the database, but vote.php is in a seperate window opened using javascript (basicly a pop-up). but for someone and isnt sending $id back to vote.php so it can know who voted anyone got any ideas on how to fix this?

[visualAd]

You need to give the ID a name:

<form action="/vote.php?id=<?php echo($id) ?>&vote=true">

Best practice is also to use full PHP tags, as some web hosts don't have short tags turned on and others may also mistake it for another HTML embedded language.

[SeeThroughGuy]

Hey, that doesnt seem to be working

[visualAd]

You can get the value of ID using $_GET['id']. Is this what you are doing? - If so could you ellaborate on whats not working.

[SeeThroughGuy]

ok, Im using the "GET" function, the first page has a link that opens a pop-up using javascript, and this is the code it uses:

<script language="Javascript" type="text/javascript">
    function opengal(id){
    window.open("thumbs/imagegal.php?id=" + id, "admin", "fullscreen=no,toolbar=no,status=no,menubar=no,scrollbars=yes,resizable=no,directories=no,location=no,width=500,height=450");
    }
</script>

<td width="10%" bgcolor="#000000"><a href="javascript:openinfo('.$id.')">Click here</a></td>

that opens a page with the information of what ever was beside "Click here", $id was definded by checking the row (from mysql_result) and that info was put into $id, it opens the new java popup alright but then when I vote, it doesnt send the id through to process it into the database and tele up the results.