convert address to string value?

[joey o.]

Hi

Please help. Moving from vb to C++ and can't figure how to get the string value of the address for something like this:

#include <stdio.h>

int main ()
{
	// Make 52 cards in deck
	//define suit and card value for each 
	int suit;char* cardNom;

	for (int i=1;i<=52;i++)
	{
	  suit = i / 13;
	  switch (suit)
	  { case 0: cardNom = "Spades";
	            break;
	    case 1: cardNom = "Hearts";
	            break;
	    case 2: cardNom = "Clubs";
	            break;
	    case 3: cardNom = "Diamonds";
	            break;
	  }

	 switch (i)
              { case 0:  cardNom = "Ace of " + char(cardNom);
	             break;
	    case 10: cardNom = "Jack of " + char(cardNom);
				 break;
	    case 11: cardNom = "Queen of " + char(cardNom);
				 break;
	    case 12: cardNom = "King of " + char(cardNom);
				 break;
	    default: cardNom = char(i + 1) + " " + char(cardNom);
                 break;
	  }
	  printf ("\nCard number: %d" , i);
	  printf (" is the %d" ,char(cardNom));
	}

  return 0;
}

[CornedBee]

Learn about proper string handling in C, or perhaps in C++. (C++ is easier, but C is closer to what you're already trying to do.) malloc, free, strcpy, strcat and strlen in C. std::string in C++.

[aewarnick]

You're handleing the cases like c++ strings although you're a little off. Make cardNom a string and use it like so:
case 0: cardNom += "Ace of " + cardNom; break;