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Thread: mysql insert thingy wont work

  1. #1

    Thread Starter
    Fanatic Member nabeels786's Avatar
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    mysql insert thingy wont work

    PHP Code:
            $link mysql_connect("localhost""fragblast""mypass");

            
    mysql_select_db("fragblast");

            
    $sql "insert into articles(name,email,gamename,system,link,ss1,ss2,ss3) values ('$name','$email','$gamename','$system','$path','$ss1','$ss2', '$ss3')";

            
    $result mysql_query($sql);

             
    // Closing connection
             
    mysql_close($link); 

    it doesnt give any errors, but when i check the table, theres nothing in there.

    any ideas? im fairly new to mysql

    thanks
    Last edited by nabeels786; Mar 20th, 2002 at 03:05 PM.
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  2. #2
    PowerPoster
    Join Date
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    Re: mysql insert thingy wont work

    Quote Originally Posted by nabeels786
    PHP Code:
            $link mysql_connect("localhost""fragblast""mypass");

            
    mysql_select_db("fragblast");

            
    $sql "insert into articles(name,email,gamename,system,link,ss1,ss2,ss3) values ('$name','$email','$gamename','$system','$path','$ss1','$ss2', '$ss3')";

            
    $result mysql_query($sql);

             
    // Closing connection
             
    mysql_close($link); 

    it doesnt give any errors, but when i check the table, theres nothing in there.

    any ideas? im fairly new to mysql

    thanks
    try this
    PHP Code:
    <?php
    $server 
    "location_of_server_here";
    $db_user "database_username";
    $db_pass "database_password";
    $database "database_name";
    $tablename "database_table_name";

    ////NOTES
    ////
    ////IF YOUR FIRST INPUT FIELD NAME IS CALLED INPUTONE THEN
    ////$FORM_INPUT_FIELD_NAME_ONE WOULD BE SPECIFIED AS:
    ////$INPUTONE

    $connection mysql_connect("$server""$db_user""$db_pass");
    $db mysql_select_db("$database"$connection);
    $query "INSERT INTO $tablename (`DATABASE_COLUMN_NAME_ONE`,`DATABASE_COLUMN_NAME_TWO`) VALUES ('$FORM_INPUT_FIELD_NAME_ONE','$FORM_INPUT_FIELD_NAME_TWO')";
    $result mysql_query($query$connection);

    ////PRINT A MESSAGE TO THE SCREEN TO SAY ADDITION SUCCESSFUL
    echo "Yeah baby yeah!  Addition Successful!";
    ?>

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