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Thread: batch file question

  1. #1

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    batch file question

    How can i concatenate 2 strings in a batch file? I have for example "abc" and "def", and i want to turn it in "abcdef". How should I do it?

    Note that I really HAVE that quotes in the string, how do I take them off?
    \m/\m/

  2. #2
    Ex-Super Mod RobDog888's Avatar
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    Re: batch file question

    The double quotes write to a file when you use the Write file operator. Change it to something
    like ... Print #1, "abc" and you will get in your batch file abc.
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    Re: batch file question

    I dont want to write to a file, I just want to have something like a var..is it even possible at all in a batch file?

    My batch file will receive as arguments this: "C:\" and "lol.jpg"
    and i want it to be able to call my other program with this as argument "C:\lol.jpg"

    as another question, is there any command in batch files to convert a short filename to a long filename?

    as a yet another question, is it possible at all in the registry to pass as a argument (in folder extension thing) only the path of clicked file, or only the filename instead of passing the full pathfilename?
    \m/\m/

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    Ex-Super Mod RobDog888's Avatar
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    Re: batch file question

    In your batch file you can receive passed parameters like so...
    Code:
    REM %1 = SomeFileNameToSearchForWithAnyExtension
    Dir %1.* /s
    This takes a parameter of a filename without the extension to do a search for
    in the DOS command window. The "%" sign is like a variable to receive
    passed parameters from the command line or shelled parameters, etc.
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    Re: batch file question

    You are not getting my point. If i have a "C:\" path and try to search for the wildcard "*.jpg" I can't just put

    Dir %1%2 as it will result as "C:\""*.jpg"
    \m/\m/

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    Re: batch file question

    It worked for me. Here is my demo code.
    VB Code:
    1. Option Explicit
    2.  
    3. Private Declare Function ShellExecute Lib "shell32.dll" Alias "ShellExecuteA" (ByVal hwnd As Long, ByVal lpOperation As String, _
    4. ByVal lpFile As String, ByVal lpParameters As String, ByVal lpDirectory As String, ByVal nShowCmd As Long) As Long
    5.  
    6. Private Const SW_SHOWNORMAL As Long = 1
    7.  
    8. Private Sub Command1_Click()
    9.     Open "D:\Development\Test2.bat" For Output As #1
    10.         Print #1, "Dir %1%2.* /s"
    11.     Close #1
    12. End Sub
    13.  
    14. Private Sub Command2_Click()
    15.     ShellExecute Me.hwnd, "Open", "C:\Windows\System32\Cmd.exe", " /K D:\Development\Test2.bat D:\Development\ Test2", "D:\Development", SW_SHOWNORMAL
    16. End Sub
    Attached Images Attached Images  
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    Re: batch file question

    You are still not getting my point...the text thats being passed has quotes AROUND IT so what I get is not C:\ like in your example but it's "C:\"
    \m/\m/

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    Re: batch file question

    Anyone...?
    \m/\m/

  9. #9
    Ex-Super Mod RobDog888's Avatar
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    Re: batch file question

    Can you post your code, maybe there is some other reason. If you are receiving it like "C:\""*.jpg" then
    it must be the way your passing it or in your batch file your placing double quotes around the variables?
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  10. #10

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    Re: batch file question

    The program that's giving the "C:\" as argument can't be changed, so I just have to work with it.

    What I need is some kind of way of manipulate strings through the batch file so I can take the quotes off and just do %path_without_quotes/*.jpg like you said
    \m/\m/

  11. #11
    Ex-Super Mod RobDog888's Avatar
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    Re: batch file question

    If you could strip out the double quotes before they are sent to the batch file then you could use the vb Replace
    function. I dont think that there is a way to do it in DOS but I will look.
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