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Feb 17th, 2005, 05:34 PM
#1
Thread Starter
New Member
solving 2tanx+x=0
need 2 find the turning point of the graph f(x)=cosx-xsinx so i differentiatied this and got f'(x)=-2sinx-xcosx
so i made this equal to 0 and worked my way down as follows:
0=-2sinx-xcosx
2sinx=-xcosx
2tanx=-x
2tanx+x=0
i dont kno where to go from here, any ideas.
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Feb 22nd, 2005, 10:03 AM
#2
Re: solving 2tanx+x=0
The trivial solution is, obviously, x = 0.
The tan(x) plot vs x has infinite branches and there's one solution to your equation for each branch (plot both 2tan(x) and -x and you'll see both curves have infinite interceptions). If you need to find any of these, other than x = 0, then you must solve the equation by numerical methods as it can't be solved analytically.
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Feb 22nd, 2005, 07:50 PM
#3
Frenzied Member
Re: solving 2tanx+x=0
The Newton iterative method should work. To find a zero of F(x), iterate the following.
NextX = X - F(X) / F'(X)
Guess at an initail value, computer NextX. then use NextX to compute another value. This usually converges to a correct value.
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