Simple algebra question

[abcdefg]

My math is rusty because Im not sure how to get this answer 3y^2-2x^3=C.
I have y^2/2-x^3/3=C and im solving for C. I subtract the x fraction and have y^2/2-x^3/3=C But im guessing thats wrong. What steps would I need to get to the right answer?
Thanks

[Zachtk8702]

hey I assume ^ means to the power of..... Use ( ) to seperate things......


Ex.
y^2/2-x^3/3=C

y to the power of 2,divided by 2,minus x to the power of 3 divided by 3 eqals C.......Is this correct or am I mistaken?

[sql_lall]

Hmm....i'm guessing this has something to do with calculus / integration, and C is some constant.

Because, if you have:
y²/2-x³/3 = C

and multiply it by six you get:
3y²-2x³ = 6C

which is the same as your 'answer', but with 6C instead of just C
however, if this is integration, or if C is some unknown constant, then you can replace 6C with C, and you get the same as the answer

[anna69]

3 unknowns, 1 equation, no can do.

[choey2k5]

3 unknowns, 1 equation, no can do.

what're you talking about?
he's not trying to solve the equation, but just trying to simplify it.
sql_lall is right, if the equation is a result of integration.