Complex numbers

[Purifier]

Hi all,

please, can anyone help me with this equation:

3(Z^3) + 2(Z^2 ) + 6Z + 4 = 0

I switched to trigonometry representation using Moivere rule, but couldn't continue...

I came up with:

3r^3(cis 3a) + 2r^2(cis 2a) + 6r(cis a) = -4(cis 360k)

or if you want:

3r^3(cis a)^3 + 2r^2(cis a)^2 + 6r(cis a) = -4(cis 360k)

but what's now?

Thank you very much...

[Jacob Roman]

3(Z^3) + 2(Z^2 ) + 6Z + 4 = 0

Is'nt this more like Algebra than Trig?

The answers -0.66666666

[Arachnid13]

and i thought complex numbers was the same as imaginary numbers, i.e. the square roots of negative values.... this isnt quite what i was expecting to see in this post!

[azteched]

Complex numbers are numbers with both real and imaginary parts: the general complex number is x + iy where x is the real component, and y the imaginary component.