Question

[Cameron Ylimaki]

is this the way that you input information into a program from a keyboard

Temperature = Keyboard.readint();

cause it does not seem to work

dooes anyone know another way to input information from a keybord in java

[Dillinger4]

No

[Cameron Ylimaki]

how do you do it then???

[Dillinger4]

Sorry i was just having a little fun. Do you want to read input from the console? The following code just reads in what you typed at the command line and spits it back out, then terminates.

 import java.io.*; 
 
 public class Q{
  public static void main(String[] agrs){
  
  try{
   BufferedReader buff = new BufferedReader(new InputStreamReader(System.in));
   System.out.println(buff.readLine()); 
  }catch(IOException e){
    System.out.println(e);
   }
  }
 }

[Cameron Ylimaki]

yup that is what i need thanks

[Dillinger4]

[Cameron Ylimaki]

actually How would i put that lets say number into a variable that i made

[Dillinger4]

readLine() returns a String. So the following would store the string returned into the s variable which has a type of String. String s = buff.readLine(); If you want to store the returned String into a integral type you have to use the parseType(String s) methods found in the Wapper classes such as java.lang.Integer. Then you could do somthing like the following. int i = Integer.parseInt(buff.readLine()); but be prepared to catch a NumberFormatException incase what is being passed into the parseType() method is not a integral representation.