Array Problems

[shishkabob]

Ok, I spent some time working on these, but I can't seem to think like a programmer yet. Could someone plz reply on how I would solve these problems?

Here are the problems.

1. Given an int num[max]
(we allready know the average)

Find and show the number closest to the average.

ex. 10, 6, 9, 10, 12 It would show 6 and 9, sence the average is 7.

2. Write the code that will find the average, then show the average and all of the numbers above the average.

ex. 10, 6, 9, 10, 12 It would show 7, 9, 10, 10, 12 but not the 6 because it is less than the average.

Plz help, this is for my computer science class, and it's due tomarow, and I can't seem to figure these 2 out.

[shishkabob]

could you guys please hurry, I'm kinda in a rush... (got to turn this in tomarrow)

[Technocrat]

I dont think anyone is going to do your homework. If you have some questions or problems I am sure we can point you in the right direction.

[Megatron]

Show us what you have so far

[shishkabob]

This isnt the entire assignment.... Oh well. Here is what I have so far.

// Problem 2

#include <iostream.h>

void main()
{
	int num[5];
	int MAX = 5;

	for (int i2 = 0; i2 < MAX; i2++)
	{
		cout << "Input Scores " << i2 + 1 << "  ";
		cin >> num[i2];
	}

	for (int a=0; a < MAX; a++)
	{
		int AVG[a] = 0;
		for (int i = 1; i < MAX; i++)
		{
			AVG[a] = AVG[a] + num[i];
		}

	AVG[a] = AVG[a] / MAX;
	}

	for(int b = 0; b < MAX; b++)
	{

		if (num[b] > AVG)
			cout << num[b];
		
	}
	

}

[shishkabob]

when I do this, I get 4 errors... can anyone help me?

[brown monkey]

Originally posted by shishkabob
[B]This isnt the entire assignment.... Oh well. Here is what I have so far.

// Problem 2

#include <iostream.h> // Standard is <iostream>.

// using std::cout;
// using std::cin;

void main() // It's int main() not void.
{
	int num[5];
	int MAX = 5; // It's const int if we define constant variable.

	for (int i2 = 0; i2 < MAX; i2++)
	{
		cout << "Input Scores " << i2 + 1 << "  ";
		cin >> num[i2];
	}

	for (int a=0; a < MAX; a++)
	{
		int AVG[a] = 0; // AVG is in the scope of this loop.
		for (int i = 1; i < MAX; i++)
		{
			AVG[a] = AVG[a] + num[i];
		}

	AVG[a] = AVG[a] / MAX;
	}

	for(int b = 0; b < MAX; b++)
	{

		if (num[b] > AVG) // AVG is not accessible here. Remember, you define it inside the second loop. And AVG is an array.
			cout << num;
		
	}

// return 0;
	

}

Hope this helps.

[Arc]

Originally posted by shishkabob
could you guys please hurry, I'm kinda in a rush... (got to turn this in tomarrow)

Hahaha, good lord. That is hillarious.