|
-
Oct 27th, 2004, 10:33 PM
#1
Thread Starter
Dazed Member
find x % needed to double value in 5 years?
A 100 percent increase over five years is a compound annual growth rate of approximately 15 percent a year. How would i find the percent needed? (10 * 1.15)5 = 20 is correct but how do i get the %? Thanks.
Last edited by Dilenger4; Oct 30th, 2004 at 07:24 AM.
-
Oct 27th, 2004, 11:09 PM
#2
Thread Starter
Dazed Member
I think i have it.
% CAGR = ((Ending Value / Initial Value) ^ ( 1 / # of periods) - 1) * 100
((20/10) ^ (1/4)-1) *100 = 59.5
59.5/4 = 14.9%
Is there a simpler way to find out the % needed to double a know value over a period of time? (10 * x)5 = 20
-
Oct 28th, 2004, 03:47 PM
#3
Fanatic Member
base * (1+interest)^years = total
1 * (1+x)^5 = 2
1 + x = 2 ^ (1/5)
x = 2 ^ (1/5) - 1 =~ .1487 = 14.87%
Don't pay attention to this signature, it's contradictory.
-
Oct 28th, 2004, 06:53 PM
#4
Thread Starter
Dazed Member
Seems pretty clear except for the line.
base * (1+interest)^years = total
1 * (1+x)^5 = 2
1 + x = 2^(1/5)
x = 2 ^ (1/5) - 1 =~ .1487 = 14.87%
I understand that you have to shift everything to one side to isolate x
but how is the power shifted? if the power is ^ 5 why does it end up being ^ 1/5? Thanks for the help.
-
Oct 29th, 2004, 03:10 AM
#5
A power of 1/5 is the same as the fifth root!
So you have (a)^5=b , take the fifth root of both and you have
a=(b)^1/5.
You're welcome to rate this post!
If your problem is solved, please use the Mark thread as resolved button
Wait, I'm too old to hurry!
-
Oct 30th, 2004, 07:24 AM
#6
Thread Starter
Dazed Member
Ah ok i see now. Pretty cool.
Posting Permissions
- You may not post new threads
- You may not post replies
- You may not post attachments
- You may not edit your posts
-
Forum Rules
|
Click Here to Expand Forum to Full Width
|