|
-
Oct 28th, 2004, 01:24 PM
#1
Thread Starter
Lively Member
busy,busy,busy...
could someone help me out?
i need a sub written up that will take a 2 dimensional matrix of user defined data {2 integers representing fractions}, build a new matrix from the rows that contain only those elements where the denominators are 3, then simultaneously solveing that matrix to determine the most minimal set of equations that require the sequence of integer elements to be divisible by 3.
I'll be in the MAC room working on 27 xerox jobs. Get me when its ready.
-Lou
-
Oct 28th, 2004, 05:22 PM
#2
All you matricies are belong to us.
-
Oct 28th, 2004, 11:32 PM
#3
Re: busy,busy,busy...
Originally posted by Something Else
could someone help me out?
i need a sub written up that will take a 2 dimensional matrix of user defined data {2 integers representing fractions}, build a new matrix from the rows that contain only those elements where the denominators are 3, then simultaneously solveing that matrix to determine the most minimal set of equations that require the sequence of integer elements to be divisible by 3.
I'll be in the MAC room working on 27 xerox jobs. Get me when its ready.
-Lou
Yes.
-
Oct 29th, 2004, 12:21 AM
#4
trying out a progrm to determine which jobs get printed first?
-
Oct 29th, 2004, 06:31 PM
#5
Thread Starter
Lively Member
How's This:
VB Code:
_____________FIN SOLS___________
c_0 :: + c_0 - F_0
c_1 :: Control
c_2 :: Control
c_3 :: Control
c_4 :: Control
c_5 :: + c_1 + c_3 + c_5 - sf_1
c_6 :: + c_2 + c_4 + c_6 + sf_1 + 2*F_0 - T
c_7 :: + c_4 + c_7 + (1/3)*sf_1 - (1/3)*sf_3 + (2/3)*F_0 - (1/3)*T
c_8 :: + c_1 + c_3 - c_4 + c_8 - sf_1 - F_0
c_9 :: - c_1 - c_3 + c_9 + (2/3)*sf_1 + (1/3)*sf_3 + (1/3)*F_0 - (2/3)*T
c_10 :: + c_1 + c_2 + c_3 + c_4 + c_10 + F_0 - T
c_11 :: - c_2 - c_4 + c_11 - (2/3)*sf_1 - (1/3)*sf_3 - (4/3)*F_0 + (2/3)*T
c_12 :: - c_1 + c_2 + c_4 + c_12 + sf_1 + F_0 - T
c_13 :: + c_1 + c_13 - (1/3)*sf_1 + (1/3)*sf_3 + (1/3)*F_0 - (2/3)*T
c_14 :: - c_1 - c_2 + c_14 - F_0
c_15 :: + c_2 + c_15 + (1/3)*sf_1 - (1/3)*sf_3 + (2/3)*F_0 - (1/3)*T
c_16 :: - c_2 - c_3 + c_16 - F_0
c_17 :: + c_3 + c_17 - (1/3)*sf_1 + (1/3)*sf_3 + (1/3)*F_0 - (2/3)*T
c_18 :: - c_3 - c_4 + c_18 - F_0
sf_0 :: + sf_0 - F_0
sf_1 :: Control
sf_2 :: + sf_1 + sf_2 + 2*F_0 - T
sf_3 :: Control
sf_4 :: + sf_3 + sf_4 + F_0 - 2*T
sf_5 :: + sf_5 - F_0 - T
sf_6 :: + sf_6 - F_0 - T
F_0 :: Control
F_1 :: + 2*F_0 + F_1 - T
F_2 :: + F_0 + F_2 - 2*T
F_3 :: - 2*F_0 + F_3 - 2*T
T :: Control
becomes a more manageable
VB Code:
_____________DIV_3_SOLS___________
sf_1 :: + sf_1 - sf_3 - F_0 - T
Now, substitute {+ sf_1 - sf_3 - F_0 - T + 3*PHI(1) = 0} into final sols:::
_____________TRULY_FINAL_SOLUTIONS___________
c_0 :: + c_0 - F_0
c_1 :: Control
c_2 :: Control
c_3 :: Control
c_4 :: Control
c_5 :: + c_1 + c_3 + c_5 - sf_3 - F_0 - T + 3*PHI(1)
c_6 :: + c_2 + c_4 + c_6 + sf_3 + 3*F_0 - 3*PHI(1)
c_7 :: + c_4 + c_7 + F_0 - PHI(1)
c_8 :: + c_1 + c_3 - c_4 + c_8 - sf_3 - 2*F_0 - T + 3*PHI(1)
c_9 :: - c_1 - c_3 + c_9 + sf_3 + F_0 - 2*PHI(1)
c_10 :: + c_1 + c_2 + c_3 + c_4 + c_10 + F_0 - T
c_11 :: - c_2 - c_4 + c_11 - sf_3 - 2*F_0 + 2*PHI(1)
c_12 :: - c_1 + c_2 + c_4 + c_12 + sf_3 + 2*F_0 - 3*PHI(1)
c_13 :: + c_1 + c_13 - T + PHI(1)
c_14 :: - c_1 - c_2 + c_14 - F_0
c_15 :: + c_2 + c_15 + F_0 - PHI(1)
c_16 :: - c_2 - c_3 + c_16 - F_0
c_17 :: + c_3 + c_17 - T + PHI(1)
c_18 :: - c_3 - c_4 + c_18 - F_0
sf_0 :: + sf_0 - F_0
sf_1 :: + sf_1 - sf_3 - F_0 - T + 3*PHI(1)
sf_2 :: + sf_2 + sf_3 + 3*F_0 - 3*PHI(1)
sf_3 :: Control
sf_4 :: + sf_3 + sf_4 + F_0 - 2*T
sf_5 :: + sf_5 - F_0 - T
sf_6 :: + sf_6 - F_0 - T
F_0 :: Control
F_1 :: + 2*F_0 + F_1 - T
F_2 :: + F_0 + F_2 - 2*T
F_3 :: - 2*F_0 + F_3 - 2*T
T :: Control
-
Oct 31st, 2004, 12:14 AM
#6
Originally posted by Something Else
How's This:
VB Code:
_____________FIN SOLS___________
c_0 :: + c_0 - F_0
c_1 :: Control
c_2 :: Control
c_3 :: Control
c_4 :: Control
c_5 :: + c_1 + c_3 + c_5 - sf_1
c_6 :: + c_2 + c_4 + c_6 + sf_1 + 2*F_0 - T
c_7 :: + c_4 + c_7 + (1/3)*sf_1 - (1/3)*sf_3 + (2/3)*F_0 - (1/3)*T
c_8 :: + c_1 + c_3 - c_4 + c_8 - sf_1 - F_0
c_9 :: - c_1 - c_3 + c_9 + (2/3)*sf_1 + (1/3)*sf_3 + (1/3)*F_0 - (2/3)*T
c_10 :: + c_1 + c_2 + c_3 + c_4 + c_10 + F_0 - T
c_11 :: - c_2 - c_4 + c_11 - (2/3)*sf_1 - (1/3)*sf_3 - (4/3)*F_0 + (2/3)*T
c_12 :: - c_1 + c_2 + c_4 + c_12 + sf_1 + F_0 - T
c_13 :: + c_1 + c_13 - (1/3)*sf_1 + (1/3)*sf_3 + (1/3)*F_0 - (2/3)*T
c_14 :: - c_1 - c_2 + c_14 - F_0
c_15 :: + c_2 + c_15 + (1/3)*sf_1 - (1/3)*sf_3 + (2/3)*F_0 - (1/3)*T
c_16 :: - c_2 - c_3 + c_16 - F_0
c_17 :: + c_3 + c_17 - (1/3)*sf_1 + (1/3)*sf_3 + (1/3)*F_0 - (2/3)*T
c_18 :: - c_3 - c_4 + c_18 - F_0
sf_0 :: + sf_0 - F_0
sf_1 :: Control
sf_2 :: + sf_1 + sf_2 + 2*F_0 - T
sf_3 :: Control
sf_4 :: + sf_3 + sf_4 + F_0 - 2*T
sf_5 :: + sf_5 - F_0 - T
sf_6 :: + sf_6 - F_0 - T
F_0 :: Control
F_1 :: + 2*F_0 + F_1 - T
F_2 :: + F_0 + F_2 - 2*T
F_3 :: - 2*F_0 + F_3 - 2*T
T :: Control
becomes a more manageable
VB Code:
_____________DIV_3_SOLS___________
sf_1 :: + sf_1 - sf_3 - F_0 - T
Now, substitute {+ sf_1 - sf_3 - F_0 - T + 3*PHI(1) = 0} into final sols:::
_____________TRULY_FINAL_SOLUTIONS___________
c_0 :: + c_0 - F_0
c_1 :: Control
c_2 :: Control
c_3 :: Control
c_4 :: Control
c_5 :: + c_1 + c_3 + c_5 - sf_3 - F_0 - T + 3*PHI(1)
c_6 :: + c_2 + c_4 + c_6 + sf_3 + 3*F_0 - 3*PHI(1)
c_7 :: + c_4 + c_7 + F_0 - PHI(1)
c_8 :: + c_1 + c_3 - c_4 + c_8 - sf_3 - 2*F_0 - T + 3*PHI(1)
c_9 :: - c_1 - c_3 + c_9 + sf_3 + F_0 - 2*PHI(1)
c_10 :: + c_1 + c_2 + c_3 + c_4 + c_10 + F_0 - T
c_11 :: - c_2 - c_4 + c_11 - sf_3 - 2*F_0 + 2*PHI(1)
c_12 :: - c_1 + c_2 + c_4 + c_12 + sf_3 + 2*F_0 - 3*PHI(1)
c_13 :: + c_1 + c_13 - T + PHI(1)
c_14 :: - c_1 - c_2 + c_14 - F_0
c_15 :: + c_2 + c_15 + F_0 - PHI(1)
c_16 :: - c_2 - c_3 + c_16 - F_0
c_17 :: + c_3 + c_17 - T + PHI(1)
c_18 :: - c_3 - c_4 + c_18 - F_0
sf_0 :: + sf_0 - F_0
sf_1 :: + sf_1 - sf_3 - F_0 - T + 3*PHI(1)
sf_2 :: + sf_2 + sf_3 + 3*F_0 - 3*PHI(1)
sf_3 :: Control
sf_4 :: + sf_3 + sf_4 + F_0 - 2*T
sf_5 :: + sf_5 - F_0 - T
sf_6 :: + sf_6 - F_0 - T
F_0 :: Control
F_1 :: + 2*F_0 + F_1 - T
F_2 :: + F_0 + F_2 - 2*T
F_3 :: - 2*F_0 + F_3 - 2*T
T :: Control
Yes.
Posting Permissions
- You may not post new threads
- You may not post replies
- You may not post attachments
- You may not edit your posts
-
Forum Rules
|
Click Here to Expand Forum to Full Width
|
Reply With Quote
