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Thread: A Trig/Calc Problem

  1. #1

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    A Trig/Calc Problem

    I Just thought this up, so I don't have the answer to it.

    An airplane traveling at a constant speed of 150 km/h receives report that a tropical storm is heading its way. As the Pilot hears the report, he feels the wind start to pick up. The wind is coming in at a 90* angle from the airport and is accelerating at a constant speed of 20km/h^2. The airplane is 50 km from the airport. What is the rate at which the airplane will have to change its direction (in degrees) in order to keep a straight path to the airport. Will the airplane make it?

    Again I just thought this up, so I don't even know if our Pilot will make it. (but Now I can start to work on it.) Enjoy.

    [Spell checked, and wind acel changed to faster speed]
    Last edited by cogman; Aug 16th, 2004 at 07:21 PM.

  2. #2
    Banned dglienna's Avatar
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    without looking at his compass?

  3. #3

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    . Im going to solve it now as I have nothing better to do. looks like I stumped this forum.
    Last edited by cogman; Aug 16th, 2004 at 07:17 PM.

  4. #4

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    solved, But im A little leary of the answer I got. for those of you still that wish to do it look no further.




































































    Ok, I came out with ~18.45* per sec would have to be the rate of change. with that knowledge, he would not have made it.

  5. #5
    Banned dglienna's Avatar
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    you can try to solve my recursive math problem...

    btw - it doesn't have to be done recursively, just have each number be different, except when it represents the same letter throughout the puzzle.


  6. #6
    Fanatic Member alkatran's Avatar
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    20 km/h^2 = 20*1000/60/60/60/60 m/s^2 = 0.00154 m/s^2

    Plane speed: 150 km/h = 150*1000/60/60 = 41.7 m/s

    Normal time to go 50 km:

    50 000 / 41.7 = 1, 199s = 1/3 hours

    Time for wind to reach the plane's speed:
    150 / 0.00154 = 97, 402 s = 27 hours

    Wind speed at .5 hours =
    .00154*30*60 = 2.7 m/s

    Angle at 2.7 m/s:
    arcsin(2.7/150) = 1 degree

    Something tells me they're gonna make it


    Oh, the rate is going to be very slow, but it won't be constant.
    Last edited by alkatran; Aug 19th, 2004 at 02:57 PM.
    Don't pay attention to this signature, it's contradictory.

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