displaying output from a sequence

[annie613]

i used this code to generate a int N. I do this using (even)n=n/2 and (odd) n=3n+1 until n becomes 1. i use a System.out.println(n); to show the results, but what if i only wanted to show that last 4 numbers in the sequence... any suggestions.. thanks in advance annie

int n = 0;
System.out.println("Please enter a number less than 100,000");
KBI.pause();
n = KBI.getint();
while(n != 1)
{
System.out.print(n + " ");
if(n % 2 == 0)
n = n / 2;
else
n = 3 * n + 1;
}
System.out.println(n);

[brown monkey]

this mate?

import java.io.*;
import java.util.*;
public class document8{
   public static void main(String[] args)throws IOException{
      BufferedReader stdin=new BufferedReader(
         new InputStreamReader(System.in));
      System.out.println("Please enter a number less that 100,000 ");
      int n=Integer.parseInt(stdin.readLine());
      int[] n2=new int[n];
      int i=0;
      while(n!=1){
         System.out.print(n+" ");
         if(n%2==0) n/=2;
         else n=3*n+1;
         n2[i++]=n;
      }
      System.out.println(n);

      //display last 4
      int j=0;
      while(--i>=0&&j++<4) System.out.println(n2[i]);
   }
} 

if not, i'm very very sorry.

[annie613]

cheers! annie
this is what i ended up with....

//arrayList code    int n = 0;    
System.out.println("Please enter a number less than 100,000");    KBI.pause();    
n = KBI.getint();    
ArrayList al = new ArrayList();    
while(n != 1)    
{      
System.out.print(n + " ");      
if(n % 2 == 0)        
n = n / 2;      
else        
n = 3 * n + 1;        
if (al.size < 4) 
{        
al.add(new Integer(n));      
} else 
{        
al.remove(3);        
al.add(new Integer(n));      
}      
}    
for (int i=0;i<4;i++) 
{      
System.out.println(((Integer) al.get(i)).toString());    
}