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Thread: Multiply Numbers

  1. Nov 27th, 2000, 01:53 PM #1
    Forest Dragon
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    Question

    Hello,

    I'm trying to multiply 2 fractions by using ONLY addition operations. Does anyone know how to do that?

    Thanks.
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  2. Nov 27th, 2000, 02:36 PM #2
    kedaman
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    For X*Y Loop X times trough R=R+X
    Use
    writing software in C++ is like driving rivets into steel beam with a toothpick.
    writing haskell makes your life easier:
    reverse (p (6*9)) where p x|x==0=""|True=chr (48+z): p y where (y,z)=divMod x 13
    To throw away OOP for low level languages is myopia, to keep OOP is hyperopia. To throw away OOP for a high level language is insight.
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  3. Nov 28th, 2000, 04:26 AM #3
    Forest Dragon
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    That doesn't work for fractions (decimal fractions that the user enters)!
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  4. Nov 28th, 2000, 04:37 AM #4
    kedaman
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    loose the decimal point, and add up both decimal places in the result, for instance:

    2.5 * 3.75
    decimal places: 1 + 2 = 3

    25 * 375
    loop 25 times, add up 375 to result

    result = 9375

    add 3 decimal places:

    9.375
    Use
    writing software in C++ is like driving rivets into steel beam with a toothpick.
    writing haskell makes your life easier:
    reverse (p (6*9)) where p x|x==0=""|True=chr (48+z): p y where (y,z)=divMod x 13
    To throw away OOP for low level languages is myopia, to keep OOP is hyperopia. To throw away OOP for a high level language is insight.
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  6. Nov 28th, 2000, 06:57 AM #5
    paulw
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    keddie,

    How do you lose the decimal points without multiplication/division? Methinks that logarithms are the way to go.

    Cheers,

    P.
    Not nearly so tired now...

    Haven't been around much so be gentle...
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  7. Nov 28th, 2000, 07:08 AM #6
    kedaman
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    paul> how about instrrev(value,".") to find it, and replace(value,".","") to removit it.

    Well i'm not sure how this scenario is set but i'm sure multiplication is done with integers.
    Use
    writing software in C++ is like driving rivets into steel beam with a toothpick.
    writing haskell makes your life easier:
    reverse (p (6*9)) where p x|x==0=""|True=chr (48+z): p y where (y,z)=divMod x 13
    To throw away OOP for low level languages is myopia, to keep OOP is hyperopia. To throw away OOP for a high level language is insight.
    Reply With Quote Reply With Quote
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