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May 7th, 2004, 07:58 PM
#6
So Unbanned
You can find this solution on-line. It's typically used with coins though. "There are 12 coins, all identical, except weight. Find the odd coin and determine whether it weighs more or less in 3 balances."
It's very possibly.
Basically:
It's breaking up the 'stones' into small groups, identifying each, then using 'stones' you know are good mixed with ones you don't to find the 'odd' one.
[edit]13?! WHAT WAS I THINKING?!  [/edit]
Last edited by DiGiTaIErRoR; May 7th, 2004 at 11:17 PM.
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