Open & Display image in win form

[carlblanchard]

Hey all firstly ive kinda got two things i wana do here

1, open file dialog, select image and display it in a picture box
2, have some access to the file for uploading to a server
(2 in more detail, ive created a object in my website application for image uploading and resizing, my CMS is in fact a windows application and ive referenced the dll for the .net website in my application, so i use use most of the code in the site. i need to be able to open/show a pic and then save it along with other data to my site. saving the data works just need to sort out the image bit.

First question, how do i display the image in a picture box
Current Code

Private Function OpenFile() As FileStream
 
        ' Displays an OpenFileDialog and shows the read/only files.
 
        Dim DlgOpenFile As New System.Windows.Forms.OpenFileDialog
        DlgOpenFile.ShowReadOnly = True
        Dim Fs As FileStream
 
        If DlgOpenFile.ShowDialog() = DialogResult.OK Then
 
            ' If ReadOnlyChecked is true, uses the OpenFile method to
            ' open the file with read/only access.
 
            If DlgOpenFile.ReadOnlyChecked = True Then
 
                Return DlgOpenFile.OpenFile()
 
                ' Otherwise, opens the file with read/write access.
 
            Else
'this below is wrong because its crashing out
                Dim Path As String = DlgOpenFile.FileName
                Dim imageStream = New FileStream(Path, System.IO.FileMode.Open, System.IO.FileAccess.ReadWrite)
 
                Me.PictureBox1.Image.FromStream(imageStream)
                Me.PictureBox1.Update()
 
            End If
 
        End If

Second question.
I guess i can just pass the stream to to asp.net because that using fileField to upload the file, is this correct ?

[MrPolite]

well just for loading the image:
remember that MOST functions in .NET DO NOT modify the value that you pass into them, but they RETURN the modified value. So when calling Image.FromStream, it is returning the opened image and not modifying the picturebox. So you would have to do this:

Me.PictureBox1.Image = Image.FromStream(imageStream)

You can simply load it this way also, if you don't want to use streams:
Image.FromFile(fileName)