How to get the high bit /low bit order?

[PT Exorcist]

I have for example the number 3021 that should have a high bit of 30 and low bit 21. How can I do this? I need it to do an FTP listing thing.

here is the thing from where i'm reading from :

This address information is broken into 8-bit fields and the value of each field is transmitted as a decimal number (in character string representation). The fields are separated by commas.

http://www.vbip.com/winsock/winsock_ftp_ref_02.asp

Thanks in advance

[Mike Hildner]

Do you mean big-endian and little-endian? Like you're sending integers from a Windows machine to a Unix machine? If so then this thread might help. http://vbforums.com/showthread.php?s=&threadid=264947

[PT Exorcist]

I don't really know if what they are saying in that topic is what I am asking about as I don't even have a very accurate idea of what it really is (LOL). I think it has something to do with the LOWORD()/HIWORD() macros(?) in c++

About the topic it requires api's and I'd like to go through the .net way

[Mike Hildner]

It would be nice if they had an example. But from reading that, it sounds like for your port of 3021 you'd send a char that equals 30 and a char that equals 21, separated by commas.

Just a guess, friend.

[PT Exorcist]

To deliver port 3021 i have to send "30,21"

30's binary string + 21's binary string = 3021's binary string. I can understand this but I don't understand how to achieve the opposite.

[Mike Hildner]

Not sure if I understand you right. You're not going to send "30,21", because that would be sending four 8-bit fields (plus the comma). I think it means you'd send "," - or in hex 0x1E,0x15.

0x1E = 30, 0x15 = 21

Of course, I'm probably wrong.

[PT Exorcist]

Yes you're wrong. They will be sent with the ip bytes separeted by comas more the port (the two values i want to know how to get separeted by comas)

The thing is how am i going to get the damn 8-bit port values?

Take the following as example:

    PORT 213,13,237,218,18,27
200 Port command successful.
    Opening data connection IP: 213.13.237.218 PORT: 4635.

[Mike Hildner]

Yes you're wrong.

That made me lol. Too funny.

The example helps. Haven't tried any code (not even sure if I know how) but it's pretty easy to get to the bits and bytes of it.

In your previous post, it looks like port 4635 = 18,27. Let's get it on...

4635 in binary = 1001000011011

Take the right 8 bits = 00011011 = 27
Take the left 8 bits (left pad with zeros) = 00010010 = 18

You can leave the right 8 bits alone, but need to multiply the left 8 bits by 256 because they're shifted left 8 bits.

So now you have 27 + (18 * 256) = 4635

Of course, I may be wrong.

Mike

[PT Exorcist]

Yeah I think that it is. Ill try it this night when i get back home