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Feb 7th, 2004, 05:30 AM
#1
Thread Starter
Conquistador
log + sound stuff
L1 = 10 log (x)
what is the effect on L1 if x is doubled
and
what is the effect on x if L1 is doubled
Thanks!
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Feb 7th, 2004, 08:55 AM
#2
Thread Starter
Conquistador
L1 = 10 log x
L2 = 10 log 2x
(10 ^ L1) ^ 1/10 = ((10 ^ L2) ^ 1/10) / 2
10 ^ L1 * 2^10 = 10 ^ L2
1024 * 10 ^ L1 = 10 ^ L2
1024 = (10 ^ L2)/(10 ^ L1)
log (1024) = L2 log 10 - L1 log 10 = L2 - L1
.'. L1 is increased by log (1024) ~= 3
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