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  1. Jan 25th, 2004, 05:55 PM #9
    DiGiTaIErRoR
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    3^3^3 = 3^(3^3) <> (3^3)^3

    The rule is, the highest power gets calculated first.

    (2^3+4^2)^2^4

    If you think about this problem. You should do 2^4 first. Then (...)^16.
    Last edited by DiGiTaIErRoR; Jan 25th, 2004 at 06:00 PM.
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