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Dec 21st, 2003, 06:08 PM
#1
Thread Starter
Fanatic Member
The holiday challenge!
Make an equation that will draw a bell. It doesn't matter how it's rotated etc, anything on the bell (like a ribbon, haha that'd be hard) is ++points.
Don't pay attention to this signature, it's contradictory.
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Dec 21st, 2003, 07:37 PM
#2
Lively Member
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Dec 21st, 2003, 07:42 PM
#3
Thread Starter
Fanatic Member
Nice!
Now, do it with one equation
Don't pay attention to this signature, it's contradictory.
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Dec 21st, 2003, 08:13 PM
#4
Thread Starter
Fanatic Member
theorising here
sqr((X^3 + 1 + [sqr(X+1)^2-(x+1)] + [sqr(-x + 5)^2 - (-x + 5)])^2)
Now let me explain that.
the point of doing sqr(equation^2) is because we get both roots, so the bottom of the bell if below the line (mirrored from top).
the last 2 things I add, add 0 IF sqr(X + 1) is valid. Otherwise the equation is null and no point is draw. In a way, it's like saying X > -1.
It's probably a pretty messed up bell, I didn't look at it yet.
Don't pay attention to this signature, it's contradictory.
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Dec 22nd, 2003, 12:20 AM
#5
Hyperactive Member
What horrible looking formulae. Ever since I've viewed a LATEX document I hardly like looking at any other. Though, the formulae themselves are quite clever.
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