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Nov 30th, 2003, 06:30 AM
#11
Lively Member
Right, so if the probability is 4/3 as you suggest, how come the number of actual occurences is greater than the number of possible occurences...
Your logic for the entire last post is flawed. With the coins thing, the probability you'll get heads at least once:
P(H > 0) = 1 - P(0) = 1 - (1/2)100 = 1.0000 to 4 d.p
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