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Thread: prove me wrong.

  1. #1

    Thread Starter
    Frenzied Member Acidic's Avatar
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    prove me wrong.

    let X=1

    X=1
    X^2=1
    X^2 -1 = 0
    (X+1)(X-1) = 1 (difference of two squares)
    (X+1) = 1 (divide both sides by (X+1))
    put X=1 in and:
    (1+1) = 1
    2 = 1?????
    Where is the error?

    Thios one took me a while to figure out, then, when I saw the light, I kicked myself to hard I convinced myself never to kick myself again.

  2. #2
    So Unbanned DiGiTaIErRoR's Avatar
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    (X+1)(X-1) = 1

    2*0<> 1

    should be

    (X+1)(X-1) = 0

  3. #3

    Thread Starter
    Frenzied Member Acidic's Avatar
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    well spoted, should be:

    X=1
    X^2=1
    X^2 -1 = 0
    (X+1)(X-1) = 0 (difference of two squares)
    (X+1) = 0 (divide both sides by (X+1))
    put X=1 in and:
    (1+1) = 0
    2 = 0?????

    There is obviously still a mistake somewhere

  4. #4
    So Unbanned DiGiTaIErRoR's Avatar
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    Also... x+1=x should be obviously false. Unless x = infinity!


  5. #5
    So Unbanned DiGiTaIErRoR's Avatar
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    Ok.. so

    (X+1) = 1

    is wrong.

    Especially when stated with(divide both sides by (X+1))

    Should become...

    (x-1) = 0/(x+1)

    and if x = 1...

    0 = 0

  6. #6

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    Frenzied Member Acidic's Avatar
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    Damn it I'm too tired. Right, I'm gonna get the question right this time.

    X=1
    X^2=1
    X^2 -1 = 0
    (X+1)(X-1) = 0 (difference of two squares)
    (X+1) = 0 (divide both sides by (X-1))
    put X=1 in and:
    (1+1) = 0
    2 = 0?????

    Damnit, I've gone wrong again, but I don't know where. When I did this myslef the last read 2=1. Damn it.

  7. #7
    So Unbanned DiGiTaIErRoR's Avatar
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    LOL.

    You can divide anything by 0; 0/(x-1)=0/0=undef.

    If you do, it's undefined.

    So, really..

    2=undef.

    Which makes the equation bogus.

  8. #8

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    You can divide anything by 0; 0/(x-1)=0/0=undef.
    I hope you meant:
    You can't divide anything by 0; 0/(x-1)=0/0=undef.

    as that would have been right. It fooled me for ages, I though of course you can divide by (X-1) as long as you do it to both sides. I never twigged that (X-1) was in fact 0. Maybe I need sleep.

  9. #9
    So Unbanned DiGiTaIErRoR's Avatar
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    You can... but like I said, it's undefined.

    Like you... you did, and we saw what happened.


  10. #10
    type Woss is new Grumpy; wossname's Avatar
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    Talking Another math puzle.

    OK, I got home from work, had a pint.

    watched a Dvd while drinking 2.5 pints per hour

    that was 3 1/4 hours ago, how many pints have i had to drink?

    if you can be arsed to work it out then you can have a drink on me because you're not having a fun enough time!







    The answer is: enough, i think. Puntcuation is suffering.
    I don't live here any more.

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