Given the following cryptarithm, deduce the values of A, B, C, D, and E. ABCDC -BEAAC --------- BADAD
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c-c=d => d=0 0-a=a => a=5 c-5-1=0 => c=6 b-e=5, skip this one 5-b=b => no solutions or 5-b-1=4-b=b => 4=2b => b=2 e>b (you need overflow) 2-e=5 => -e=5-2 => e=-3 = 7 (mod 10) 52606 27556 -------- - 25050
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