Need help with an equation.

[Dillinger4]

Im pretty much stuck on this one. For some reason i cant' figure out how this equation should be factored. Thanks.

x - 2(x +3) = 6
x - 2x -6 = 6
x - 2x -12 = 0
As far as i get.........

[Dillinger4]

For instance some of these are quite easy.......

-m² = 8 - 9m
0 = m² -9m + 8
(m-8)(m-1)
m² - m -8m + 8
m² - 9m + 8
m = 8,1

[NotLKH]

Originally posted by Dilenger4
Im pretty much stuck on this one. For some reason i cant' figure out how this equation should be factored. Thanks.

x - 2(x +3) = 6
x - 2x -6 = 6
x - 2x -12 = 0
As far as i get.........

from this point:

x - 2x -12 = 0

==> -x -12 = 0
==> -12 = x

or, from right to left:
==> x = -12

is this what you need?

-Lou

[Darkwraith]

If you ment x^2 -2x -12, then try completing the square.

x^2-2x=12
x^2-2x+2=14
(x-1)^2=14
x=(+/-)SQRT(14)+1

[Dillinger4]

Yes exactly Lou I didn't think to solve that way. The whole chapter revolves around solving polynomial equations by factoring so i thought i was looking at the product of two binominals. Just as (m-8)(m-1) factored equals m2 -9m + 8.