How to determine Length of number

ihave a number "hallo", or 0.00568 how can i determine the length of it?

[jbart]

Private Sub Command1_Click()
    MsgBox "Length is " & Len(Str(0.00568))
End Sub

Is this what you are looking for ?

Ya ya ... that's it... thanks
and by the way, do you know how can we find the location of a number in a series of number
0.0000005
where is the location of 5? it is not aways 5 not i try to dormat the number to 5 * 10^ n somthing like that, so i need to figure out the first number after decimal and 0
once again, tghanks

[Edneeis]

You could temporarily convert it to a string and then use the len() function. Will that accomplish what you want?

  It looks like someone just posted code for you as I was writing this

As for the second thing:

Just split(OrigNumber,".") after converting it to a string and then work with mysplit(1) in the rest of the code, that will be only what is after the decimal

[Edited by Edneeis on 10-12-2000 at 02:23 PM]

[jbart]

Similar to this ?

Private Sub Command2_Click()
    Dim NumToSearch As Double
    Dim NumToLocate As Integer
    
    NumToSearch = 0.0005
    NumToLocate = 5
    
    MsgBox InStr(1, NumToSearch, NumToLocate)
End Sub

I think it will not work as it is not always 5 and how about this one?
Y2 = 0.01
Do While Y2 < 1
z = z + 1
Y2 = Y2 * 10
Loop
Text2.Text = Y2

why i can not get y2 as 1 .. but 9.99999999

anyone help here

[kedaman]

the logaritmical solution

msgbox -int(log(0.00005)/2.30258509299405)

Guru , are you kidding me or what?
i try the example i posted... it doesn't give me 1 but give me 9.999999999999999999999 wonder why, help please

[Frans C]

dragonyian,
this page will explain you why you get these strange errors:
(Complete) Tutorial to Understand IEEE Floating-Point Errors

[kedaman]

eh sorry divide with a bit smaller number or to be really sure log(10)

So, what do you guys think i can do...
what i need is to loop and figure out how small the number is and then make it as 5 *10^6 something like that... any suggestion?

[kedaman]

Why don't you go try the ten'th logaritm?

msgbox -int(log(0.00005)/log(10))

should work now, i've tested it out

[flint]

Dragonyian: I posted this reply in the center form thread as well.

The

do while y <1

does not allow the Y varible to become 1. Your code continues to multiply Y(0.01) * 10 until the value of Y = .99

take .99 * 10 and you get 9.99

hope this helps

Flint

A man will pay $2 for a $1 item he wants. A woman will pay $1 for a $2 item that she doesn't want.

[flint]

Did this help Dragonyian?

Flint

Eating words has never given me indigestion.
— Winston Churchill: 1874-1965, British
politician, writer