The power of RND

[rino_2]

Hi,

I'm making a program that will need to randomize two numbers. The problem is that the numbers are not close to each other like 1 to 2. The numbers are something like 2 to 6. But you understand, I only want to random one of those two numbers. If I said:

intNumber = int((6 * RND) + 1)

I would get all the numbers in between aswell. I hope you understande what I'm saying here. I only want to random 2 or 6 using the random function. Could you please help?

Thank you!

[badgers]

would this work for you?
If int((6 * RND) + 1)<3 then
intNumber = 2
Else
intNumber = 6
End If

[rino_2]

Hi badgers,

Maybe I should have been a little more clear in my question. I just used 2 and 6 as an example. Really I want to randondomize one of the numbers 2 3 5 7 and 9. So I'm not too sure that way would work. I will be happy to hear any other ways you may know.

Thanks

[MartinLiss]

I think we are having a problem understanding what you mean by "randomize one of the numbers". Can you give an example of the results you would expect?

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Marty

[TheMadMonk]

just do like badgers said, but split the resulst into 5 parts

intNumber = int((5 * RND) + 1)

then:
if intNumber = 1 then Result = 2
if intNumber = 2 then Result = 3
if intNumber = 3 then Result = 5
if intNumber = 4 then Result = 7
if intNumber = 5 then Result = 9

(a case statement would be easier though)

[QWERTY]

or use this:

    Dim Done As Boolean
    Dim myNum As Integer
    Do While Not Done
        myNum = Int((9 * Rnd) + 1)
        If myNum <> 2 And myNum <> 3 And myNum <> 5 And myNum <> 7 And myNum <> 9 Then
            Done = False
        Else
            Done = True
        End If
    Loop

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Visual Basic Programmer
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PolComSoft
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