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Thread: Speed problem with current(Resolved)

  1. #1

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    I don't do your homework! opus's Avatar
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    Speed problem with current(Resolved)

    Hi I'm trying to solve this problem, but I can'T get the solution exempt by try and error. What am I doing wrong?

    Problem:

    A ship travels along a river from A to B and back. Time required for both ways is 11,5 hrs. The river has a current of 2,5 Knots(Nm/hr). The distance from A to B is 91 Nm.
    What's the speed of the ship (speed thru water!)

    I have:
    T1= Time to travel from A to B (with the current)
    T2= Time to travel from B to A (against the current)
    V= Speed of Ship (Speed thru the water)
    T2=11,5 hrs -T1
    The equation is:
    2*91= T1*(V+2,5) + (11,5-T1)*(V-2,5)

    I can convert this one back and for, but T1 and V will allways be in there. How would I get the correct value for V?

    Note 15,8 is not the coorect one, this one would assume no current and T1=T2!
    By try and error I got 16,2 Kn
    Last edited by opus; Feb 11th, 2003 at 04:53 AM.
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  2. #2
    vbuggy krtxmrtz's Avatar
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    T1 + T2 = T = 11.5 h
    Vr = 2.5 Nm/h
    d(A-B) = 91 Nm

    Time for A to B travel: T1 = d / (V + Vr)
    Time for B to A travel: T2 = d / (V - Vr)

    Add these 2 up:

    T = d[1/(V + Vr) + 1/(V - Vr)]

    The rest is easy and you come up with a second degree equation:

    V2 - (2d/T)V - Vr2 = 0

    Solving for V you get 16.212 Nm/h
    Last edited by krtxmrtz; Feb 11th, 2003 at 05:09 AM.

  3. #3

    Thread Starter
    I don't do your homework! opus's Avatar
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    Thank's, so the problem was not to start with TotalTime.
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