Hi,
I got my math test back today and I think that the teacher marked a question wrong that isn't. However I'd hate to be the kid that second-guesses the teacher and is wrong. The attached image is the question. I chose choice 4 as my answer. My teacher says that 1 is the answer. What do you think?
I don't think either of them works. If you have 24 as the diagonal length, then ABC and ACD aren't triangles. However, if you have 4 as the diagonal length, it means you can draw a ling from B to AC with length 2, which you can't.
if angle D is acute then it is possible to have 4 as the length. 24 definately doesn't work because as Kalkewl8ter stated it won't be a trangle since 11+11<24
Massey RuleZ! ^-^__Cheers!__^-^ Massey RuleZ!
Did you know that...
The probability that a random rational number has an even denominator is 1/3 (Salamin and Gosper 1972)? This result is independently verified by me (2002)!
Did you know that...
The probability that a random rational number has an even denominator is 1/3 (Salamin and Gosper 1972)? This result is independently verified by me (2002)!
Did you know that...
The probability that a random rational number has an even denominator is 1/3 (Salamin and Gosper 1972)? This result is independently verified by me (2002)!
well it also has its sides parallel, well here it is:
Massey RuleZ! ^-^__Cheers!__^-^ Massey RuleZ!
Did you know that...
The probability that a random rational number has an even denominator is 1/3 (Salamin and Gosper 1972)? This result is independently verified by me (2002)!
and that acute angle t, is the solution to the following cosine law equation:
4^2=11^2+11^2-2*11*11*cos(t)
Massey RuleZ! ^-^__Cheers!__^-^ Massey RuleZ!
Did you know that...
The probability that a random rational number has an even denominator is 1/3 (Salamin and Gosper 1972)? This result is independently verified by me (2002)!
Hi, Rh0ads
you're only half right:
You're arguing 4 can't be the correct answer since the diagonal AC (which is the one from the smaller angles) can't be shorter than 11.
You're teacher is probably putting it this way: I'm not asking for a specific diagonal
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None of the angles is stated so, the rhombus could have any other shape (i.e. more or less stretched) as long as AD and AC are 11 m. If you make the angle ADC ever smaller until it at the limit it becomes 0, then the diagonal will be 0 so, in between you have a value of the angle ADC for which 4 m is a solution.
Similarly, if you now increase the angle ADC until, at the limit you have 180 deg. the diagonal will be 22 m. Therefore, 24 m can not ever be the diagonal.
krtxmrtz, sounds like you're a teacher ....brrrrrrrrrrrrrrr
I was looking at it from a layer's position (a layer for Rh0ads)! But I guess you never had to fight for a better grade! I was nearly kicked off the university 'cause of a false grade!
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Originally posted by opus A good example for the ignore list
Absolutely. These kind of people rather belong in the boloney forum.
Btw I'd also be happy trying to solve some of these riddles on my 30 min. train ride from/to home. Only it's too crowded and sometimes you need to use paper and pen.
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Cheers!
