Fix, round etc....

[ianpaisley]

Hi,

Is there a function for cutting off a number at a specified number of decimals, rather than rounding it?

If my number is:

x = 12.6549

How can I return it to only 2,3 or whatever specified number of decimal places, like 12.6?

Fix(x) only returns the integer part.

Thanks for any help!

[holly]

just a suggestion - could you not use the format function

ie

Format(12.6549, "00.0")



I think thats the right syntax

[ianpaisley]

No format doesn't work. Still rounds it off

eg:

dim number as double
number=4.568972

picture1.print Format(number, "0.0")

This will print 4.6, rather than 4.5

Thanks anyway.

[si_the_geek]

in that case... where "dp" is the number of decimal places:

int(12.6549 * (10^ dp) ) / (10^ dp)