single instance of dialog

[purusingh]

how to display non modal dialog only one time?
I mean if it is alraady open the not to create the dialog.

[MikeyD]

Are You using VC?
You just have to set Your Dlg-ptr to NULL (e.g. in the ctor) and then check, if it is valid:

	if (!m_pDlg)
	{
		m_pDlg = new Dlg1;
		m_pDlg->Create(IDD_DIALOG1, this);
		
	}
	m_pDlg->ShowWindow(SW_SHOW);

(Don't forget to delete the ptr. in the dtor!)


Is that what You want?

Mikey

[CornedBee]

And if you're using pure API (which would be better!) here's the equivalent code:

HWND g_hDlg = NULL;

//...
if(!g_hDlg) {
  g_hDlg = CreateDialog(hInstance, MAKEINTRESOURCE(IDD_YOURDIALOG), hwnd, DlgProc);
}

[purusingh]

Thank U very much

[purusingh]

if (!m_pDlg)
{
m_pDlg = new Dlg1;
m_pDlg->Create(IDD_DIALOG1, this);

}
m_pDlg->ShowWindow(SW_SHOW);


if (!&m_pDlg)
{
m_pDlg = new Dlg1;
m_pDlg->Create(IDD_DIALOG1, this);

}
m_pDlg->ShowWindow(SW_SHOW);

Both of these codes give error in if statement.

it works without pointer
if (!m_pDlg)
{
m_pDlg.Create(IDD_DIALOG1, this);

}
m_pDlg.ShowWindow(SW_SHOW);

but how to work using pointer?