An object's data type

[CactusCat]

Don't know if what I'm about to say will make sense, so bear with me and ask if you don't understand...

When you have a class, in this case an 'Multiplier' class, how can you using the object identifier to return a value?

Example:

{
____Mulitiplier Multi;

____Multi.Number1=2;
____Multi.Number2=4;

____cout << Multi; *
}

This would return 8. I realise it's a useless class, but I'm more concerned about the * line. How could I make this line print the value '8' without having to use a line akin to "cout << Multi.result;"?

Does it have anything to do with class operators?

[MikeyD]

yes, it has something to do with an operator - in this case it's maybe the int-op.

class Multi
{
public:
	operator int() {return No1 * No2;}
	int No1, No2;
};
Multi oMulti;
oMulti.No1 = 2;
oMulti.No2 = 4;
cout << oMulti; // 8

Mikey

[CactusCat]

Congratulations x 2!

#1 for solving the problem
#2 for working out what I was trying to say!

Thanks muchly!

[CornedBee]

Tip: use code tags. Then you don't need long lines of undescores to keep your code indented.

[CactusCat]

... Not entirely sure how code tags work. Care to elaborate?

[CornedBee]

[ code]
Your code here
[/ code]

Remove the spaces.

Then your code will preserve formatting:

int main()
{
    // indentation
    printf("Hello, World!");
    return 0;
}