Help with complex if statements

[Bebo]

#include <iostream.h>
int main()
{
	int myLook;
	cout << "Rate my looks on a scale from 1 to 10\n";
	cin >> myLook;
	{
	if (myLook == 1)
		cout << "1\n";
	if (myLook == 2)
		cout << "2\n";
	if (myLook == 3)
		cout << "3\n";
	if (myLook == 4)
		cout << "4\n";
	if (myLook == 5)
		cout << "5\n";
	if (myLook == 6)
		cout << "6\n";
	if (myLook == 7)
		cout << "7\n";
	if (myLook == 8)
		cout << "8\n";
	if (myLook == 9)
		cout << "9\n";
	if (myLook == 10)
		cout << "10\n";
	return 0;
	}
}

uhh I basically want to make it so if you type in a number it will say something I have it set to say the number you type in right now, I want it so if you type in a number that is not between 1-10 that it says error or something, could someone give me some ideas or examples of what I could do to make this work the way I want it to?

Thanks

[crptcblade]

I would use a switch statement.

#include <iostream.h>

int main()
{
	int myLook;

	cout << "Rate my looks on a scale from 1 to 10\n";
	cin >> myLook;
	
	switch (myLook)
	{
		case 1:
			cout << "1\n";
			break;
		case 2:
			cout << "2\n";
			break;
		case 3:
			cout << "3\n";
			break;
		case 4:
			cout << "4\n";
			break;
		case 5:
			cout << "5\n";
			break;
		case 6:
			cout << "6\n";
			break;
		case 7:
			cout << "7\n";
			break;
		case 8:
			cout << "8\n";
			break;
		case 9:
			cout << "9\n";
			break;
		case 10:
			cout << "10\n";
			break;
		default:
			cout << "Please enter a number between 1 and 10.\n";
	}

	return 0;

}

[Bebo]

hmm that works was trying to get something working using if and else statements... reading a book and havent yet gotten to switch statements :\

Thanks for help

[crptcblade]

Well, you can use if and else if's as well, but generally a switch block is considered easier to read, especially with your type of example.

#include <iostream.h>

int main()
{
	int myLook;

	cout << "Rate my looks on a scale from 1 to 10\n";
	cin >> myLook;

	if (myLook == 1)
		cout << "1\n";
	else if (myLook == 2)
		cout << "2\n";
	else if (myLook == 3)
		cout << "3\n";
	else if (myLook == 4)
		cout << "4\n";
	else if (myLook == 5)
		cout << "5\n";
	else if (myLook == 6)
		cout << "6\n";
	else if (myLook == 7)
		cout << "7\n";
	else if (myLook == 8)
		cout << "8\n";
	else if (myLook == 9)
		cout << "9\n";
	else if (myLook == 10)
		cout << "10\n";
	else
		cout << "Please enter a number between 1 and 10.\n";


	return 0;
}

[parksie]

Why not just use cout << mylook << endl ?

[Kings]

Because he wants a number from 1 to 10?

[john tindell]

then Bebo could use

int myLook;
cout<<"Enter a Number"<<endl;
cin>>myLook;
if(myLook<=10)
cout<<myLook;

[crptcblade]

Originally posted by parksie
Why not just use cout << mylook << endl ?

I just assumed that outputting the number again was an example, not the actual purpose of the program.

[parksie]

Oh. An array could be used for a lookup, as well

[crptcblade]

Meh, he hasn't even gotten to switch yet.

[kedaman]

why should switch be taught before arrays?

[crptcblade]

I don't know, its a crazy world.

[CornedBee]

Not before arrays, but before using arrays as lookup tables.

int myLook;
cout<<"Enter a Number"<<endl;
cin>>myLook;
if(myLook<=10)
cout<<myLook;

should be

int myLook;
cout<<"Enter a Number"<<endl;
cin>>myLook;
if(myLook<=10 && myLook >=1)
  cout<<myLook;
else
  cout << "Enter a number between 1 and 10" << endl;

And it should include <iostream>, not <iostream.h>:

#include <iostream>
using namespace std;