En = Fn(B, C) + ???Fn(D)???

[NotLKH]

Originally posted by sql_lall
Part 2) The identity is 'given', so i don't know why you have to 'reach' it, as you already know it.

Good Question.
What I'm trying to do {Actually, I think I've done it} is balance an
arrangement of numbers in a symmetrical fashion. At the time I posted this thread, I was trying to balance every row so that each one adds to A + Sum(C), but I was unbalanced in terms of D. So, If I were to add elements of D to E such that every row resulted in an equation of D that equaled 0, then I would have succeeded. Certainly, if in one cell I had a +D₁ and in the same row there was a different cell containing -D₁,
then the sum of the D₁'s would automatically zero out.

However, since we also have the identity SumD_odd = SumD_even then we could zero +D₁ out by haveing -D₂ -D₄ -D₆ +D₃ +D₅ in another cell of the same row.

So, its not a matter of proveing SumD_odd = SumD_even, its a matter of useing SumD_odd = SumD_even to offer a second way of zero'ing the D's out.

Originally posted by sql_lall
Also, what do the different shapes mean (like what Does the "B1 + C1" in the oval mean??? or all the other equations in the shapes

Originally posted by kedaman
What's this for? What does the diagram illustrate? just curious

AhHa! 2 More good questions!
B1 is a variable representing a number. So is C1, and so is Every B and C, so when you see a cell with B1 + C1 then it means add B1 with C1.

Other than that, At this moment,
I'm afraid I'm unable to easily answer these questions.


Give me a day or two, I might have a satisfactory answer.

-Lou