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Thread: How do you find the slope of a Quaderaterial Line?

  1. #1

    Thread Starter
    Hyperactive Member Q_Me's Avatar
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    How do you find the slope of a Quaderaterial Line?

    How do you find "m" & "e" in the theory below?

    y = m(x^e) + b

    x1 = 1
    y1 = 1

    x2 = 2
    y2 = 8

    x3 = 3
    x3 = 18

    but what is the actual equation to find "m" and "e"?
    eg.

    mx^e = ?

    how do you get "x" out of the first side?

    m?^e = ?x?
    53323737 15 743 313402 05 740313063. 17 15 4150 743 313402 05 140393403437 5203 743 30210.


  2. #2

    Thread Starter
    Hyperactive Member Q_Me's Avatar
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    If you know the Y1, X1, Y2, X2, Y3, X3, and B what is the rest of the problem?
    53323737 15 743 313402 05 740313063. 17 15 4150 743 313402 05 140393403437 5203 743 30210.


  3. #3
    vbuggy krtxmrtz's Avatar
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    If b is known, then the problem is not difficult.

    Take, for example, the first 2 points,

    y1-b=mx1e
    y2-b=mx2e

    Divide these two:

    (y1-b)/(y2-b)=x1e/x2e=(x1/x2)e

    So now,

    e log(x1/x2)=log((y1-b)/(y2-b))

    e=log((y1-b)/(y2-b))/log(x1/x2)

    and now m can be easily calculated.

    If the (x,y) coordinates come from experimental measurements then probably not all 3 points will simultaneously comply with the equation so you'll have to try a fit by graphical or any other methods (least squares...?)

    Originally posted by Q_Me
    If you know the Y1, X1, Y2, X2, Y3, X3, and B what is the rest of the problem?

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