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Aug 4th, 2002, 08:53 AM
#1
Thread Starter
Addicted Member
well,is it difficult
2log1/2(a-3)+2xlog1/2(a-x^2)<0
(log1/2(a-3):1/2 base logarithm of( a-3))
determine a of integer to satisfy inequality with x in R?
can u help me?
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Oct 3rd, 2002, 04:17 PM
#2
What a hell of an inequality...
I don't know how to determine a, but at least this could be somewhat simplified, couldn't it?
2log1/2(a-3)+2xlog1/2(a-x^2)<0
log1/2(a-3)+xlog1/2(a-x^2)<0
log1/2(a-3)+log1/2(a-x^2)^x<0
log1/2[(a-3)(a-x^2)^x)]<0
(a-3)(a-x^2)^x<1
Now, if x could be any real number, maybe you should try to solve this by numerical -rather than analytical- methods, for a specific value of x...
Where did you get this formula from?
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