could there be a combination?

[prog_tom]

2(2^2)

3(3^3)

4(4^4)

.....

a(a^a)

What I have found, but not yet proven, I think is that in case of a = 3.

3(3^3) = 81. But we can see it this way:

(3*3)^3-1, also 81. But this notion doesn't work with a=2, or 4 or any other number I haven't test it yet.

[plenderj]

What exactly are you asking ?

[JPicasso]

I think there is a combination,

and the combination of drugs Prog_Tom has been taken,
should be written down and given to me.

I bet it's a nice place.

[plenderj]

Originally posted by JPicasso
I think there is a combination,

and the combination of drugs Prog_Tom has been taken,
should be written down and given to me.

I bet it's a nice place.

lol

[Guv]

a*a^a = a^a+1

The above should provide some insight.