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Thread: Trigonometry Calculations & other questions with math

  1. #1

    Thread Starter
    New Member
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    Talking

    First off I'm working on something to do Trig Calculations, Like changing Degrees to Radians, and being able to enter either the degrees and/or coordinates of a angle to be able to get the 6 different trig functions. Now does anyone have any help with these problems?

    Next:
    1. How can I enter in a Square root to use as a calculation? No Calc to sqr, but enter it into a txt box?

    2. Whats the best way to return a answer in fraction form?

    3. Is there a way to return a answer as a square root and not in a decimal form?

    Well Thats it for now, Thanks

    NoClue

  2. #2
    Addicted Member
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    Well, I'm not sure if I understood the first question, but I take it that you want the user to input a number, and then get the squareroot.
    I would do like this:
    Numb = Val(Text1.Text) 'The number the user inputs
    Numb = Sqr(Numb)

    As for the third, you can of course use this:
    'Numb is the number you want to write as a squareroot.
    Numb = Numb^2
    text1.text = "Squareroot of " & Numb
    That would return the answer as a square root in the textbox Text1

    As I said, it might be that I've misunderstood your questions, i'm not sure.
    If this is not what you want, please post a bit more clearer.
    I'm thinking of number two, and I will post here as soon as I've found out (I've done it for a TI-83, it's just a matter of my memory...)
    Good Luck!
    Pentax
    Wilhelm Tunemyr,
    Swede in London

    [email protected]

    "Dort, wo man Bücher verbrennt, verbrennt man am Ende auch Menschen"
    Heinrich Heine (1797-1856)

    Pravda vítezi!
    (Truth prevails!)

  3. #3
    Lively Member
    Join Date
    Aug 2000
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    125
    goto help trigonometric functions and choose Derived Math Functions

    1. can't understand your wording - Sqr function?
    2. have to write your own function to get your accuracy
    like if you want 32nds you must round to the nearest 32nd

    dim s as String
    dim x as double

    s = Str(Fix(num))
    x = num - Fix(num)

    x = Fix(x * 32 + .5)

    s = s & Str(x) & "/32"

    3. convert as in 2

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