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Sep 12th, 2002, 05:13 PM
#1
Thread Starter
Addicted Member
2 New Problems
Something new? Hmmmmm.......ok
How about an easy function problem.
And then a harder sequence problem.
1. If f(x)=9x+1 and g(x)=x^2. Find all values of x which satisfie f[g(x)]=g[f(x)]
and ....
2. If p and q belong to positive integers such that p/q=1+1/2-2/3+1/4+1/5-2/6+1/7+1/8 ... +1/478+1/479-2/480. Prove p is divisible by 641.
YL says:"Few are those who see with their own eyes and feel with their own hearts."(Einstein)
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Sep 12th, 2002, 07:06 PM
#2
Frenzied Member
1. 0
2....haven't looked at yet
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Sep 13th, 2002, 07:18 PM
#3
Thread Starter
Addicted Member
Hey the answer is 0 or -1/4 for the first one. But what about the second?
YL says:"Few are those who see with their own eyes and feel with their own hearts."(Einstein)
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Sep 14th, 2002, 09:34 AM
#4
Thread Starter
Addicted Member
Guys somebody get the second one? Alright bugz you can post your solution since nobody can do it!
YL says:"Few are those who see with their own eyes and feel with their own hearts."(Einstein)
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Sep 14th, 2002, 11:12 AM
#5
Fanatic Member
Massey RuleZ! ^-^__  Cheers!  __^-^ Massey RuleZ!
Did you know that...
The probability that a random rational number has an even denominator is 1/3 (Salamin and Gosper 1972)? This result is independently verified by me (2002)!
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Sep 14th, 2002, 11:55 AM
#6
Thread Starter
Addicted Member
YL says:"Few are those who see with their own eyes and feel with their own hearts."(Einstein)
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Sep 14th, 2002, 12:34 PM
#7
Lively Member
!
p/q= 1/1+1/2+1/3+......+1/480 - 3*1/3(1/1+1/2+....+1/160)
=1/161+1/162+....+1/480
=641/(161*480)+.....641/(...*....)
=641* N/Q
641 is the prime number so q<> 641 *k => p=641*N
...
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Sep 14th, 2002, 02:01 PM
#8
Thread Starter
Addicted Member
Last edited by SilverSprite; Sep 14th, 2002 at 02:14 PM.
YL says:"Few are those who see with their own eyes and feel with their own hearts."(Einstein)
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