removing last 5 or 6 chars

[nabeels786]

ive got a ip like: <ip>:<port>

i wanna strip teh :<port>

there what i came up with

	bool passed=false;
	for(int i=0;i<=strlen(server_name);i++){
		if(passed){
			*server_name=' ';
		} else{
			if(*server_name==':'){
				*server_name=' ';
				passed=true;
			}
		}
		*server_name++;
	}

it returns the lst 8 with the port, and i cant figure out why

[jim mcnamara]

char *buf;
buf = server_name;
buf+=strlen(server_name) -1;
while(*buf!=':'){
       *buf-- = 0x00;
}
*buf = 0x00;
}

voila...

[prog_tom]

what is 0x00?

[nabeels786]

null character

[prog_tom]

cool!! where do you see all these weird characters?

[abdul]

Originally posted by prog_tom
cool!! where do you see all these weird characters?

They are at the end of every string.

[prog_tom]

how come I never seen any of them, previously?

[Daok]

0x00 = 0

it's hexadecimal....

and what you call weird character is ASCII caracter.

in all C++ book it have an introduction about that.

[nabeels786]

Originally posted by jim mcnamara

char *buf;
buf = server_name;
buf+=strlen(server_name) -1;
while(*buf!=':'){
       *buf-- = 0x00;
}
*buf = 0x00;
}

voila...

it returns a blank

[jim mcnamara]

huh? this code prints everything up to but not inclusing the ':'

#include <stdio.h>
int main(){
 char server_name[100];

 char *buf;
 memset(&server_name,0x00,sizeof(server_name));
 strcpy(server_name,"101.101.0:asb");
 buf = server_name;
 buf+=strlen(server_name) -1;
 while(*buf!=':'){
       *buf-- = 0x00;
  }
 *buf = 0x00;
  printf("%s\n",server_name);
}

The only possible difference is that server_name here is an sz string.