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Thread: Is this correct?

  1. Aug 4th, 2002, 07:20 PM #1
    Dillinger4
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    Is this correct?

    Im working on a problem that is presented in the form of. 6x-3y / 9x2y-2. Now i know that a-n = 1 / an. So my question is why is x-3/ x2 broken down into 1 \ x[2-(-3)]?
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  2. Aug 5th, 2002, 01:12 AM #2
    DavidHooper
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    x-3 / x2
    = x-3 * x-2
    = x-3-2
    = 1 / x2+3
    = 1 / x2-(-3)

    All comes out as x-5
    There are 10 types of people in the world - those that understand binary, and those that don't.
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  3. Aug 5th, 2002, 12:00 PM #3
    Dillinger4
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    I thought 1 / x2-(-3) would come out to x5
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  4. Aug 5th, 2002, 12:45 PM #4
    bugzpodder
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    x^(2-(-3)) comes out to be x^5. 1/x^(2-(-3)) comes out to be x^(-5)
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  6. Aug 5th, 2002, 12:56 PM #5
    Dillinger4
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    Ah ok.
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