syntax question

[CGB]

Whats wrong with this code (Faze1 is a random number from 1-3, Face is a picturebox:

If Faze1 = 1 Then FACE = (App.Path & "\Antonio.bmp")

This continues up to 3 with a different .bmp picture each time, but the program never show the picture it highlights the & and comes up with the error 'Type Mismatch'
I don't have the MSDN help collection so I can't find the correct usage.
Thanks for any help.

you are trying to send a string value to Face, not a picture!

try
'#####
Face.loadpicture(Path)
'#####
instead.

MSDN has a website that you can look at. It is a mirror of the CD's

[Edited by wossname on 08-26-2000 at 11:23 AM]

[CGB]

Thanks!

[CGB]

but that doesn't work!
i just tried it

[CyberSurfer]

Try this:

[code]
dim path as string
dim faze1 as integer

path = App.path + "\Antonio.bmp"

if faze1 = 1 then

face.picture = path

else

end if

[CGB]

thanks, i'll try it

[CGB]

it still doesn't work

[Crazy D]

You need to use

Set FACE.Picture = LoadPicture(sPath)

Face.Picture = LoadPicture(App.Path & "\Antonio.bmp")

It should work.

Hope this helps.

[CGB]

it now says, in an error window and you have the choice to debug or end:

object variable or with block variable not set

any ideas?

What part does it highlight?

[CGB]

Face.Picture = LoadPicture(Path)

that part

Try:

Set Face.Picture = LoadPicture(App.Path & "\Antonio.bmp")

Even though the first suggestion worked on my computer.

[CGB]

i'll give it a go.
if not do you mind checking over the full code related to this prob.? (its not much)
ok back in a sec..

[CGB]

i had the picture dimmed as a picture box and was making one other idiotic mistake.
i tried what you suggested 1st time and it worked.
thanks for your help.
you probably wont be asking me for any but thanks.