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Thread: How to equate 2=3?

  1. #1

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    How to equate 2=3?

    Do anyone know how to equate 2 = 3 (using square and square root)?

    I knew a long back but I forgot this now.

    (Just I was betting with my firend.)

    Thanks
    Last edited by vsusi; May 21st, 2002 at 01:49 PM.

  2. #2
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    why'd you bet that 2==3???

    the equation has an error in it that usually slips by most people...so at first look they make it look like 2==3

  3. #3
    Destined Soul
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    Steve's right. If the proof resulted in 2 = 3, then there would HAVE to be an error (or some violation) in the math to allow this. I remember seeing a proof on 1+1=1 or something like that, and it involved doing something like:

    1+1 =1
    a+a = b
    ....
    a/(b-a) = something

    and then they continued on with the math using the (b-a) as if it was non-zero.

    Anyhow, I'm super bored, so I thought I'd share that, and one more thing.

    If 2 = 3, then it should be that 2 = 3 = 4 = 5 = ... ??

    Oh well, back to work. =P

    Destined

  4. #4
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    I wish that worked on math tests
    x = 2

    the answer is 265!

    but 2 = 265 lol

    yeah sorry I'll go now

  5. #5
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    The proof for 1+1=1 went like this:

    Applying a^2 = b^2 + c^2 to an equilateral right-angled triangle, s=1.

    Therefore 1^2 = 1^2 + 1^2

    1 = 1 + 1

    Or something like that...
    Abhishek

  6. #6
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    you can't have an equilateral right triangle

  7. #7

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    Friends

    I know some of you people were curious about whether the question is right or wrong.

    I can tell you that the question is correct using Mathematics bug.

    Clue: Assume a number. Let us say 2.

    1. Square it. (2²= 4)

    2. Now take a square root of 4. (It gives two values. +2 and -2)

    3. This is a bug in Math. I used only +2. But now I got -2. Now +2 is equalent to -2. If that is equal then 0 = 4 (Am I right)

    This will be a simple proof of 0 = 4

    2 = 2
    Square it
    4 = 4
    Sq Root it. I can assume +2 on one side and -2 on another side.
    2 = -2
    When sending 2 to other side
    0 = -2 + (-2)

    0 = 4


    BTW SteveCRM is correct. Pythagoras says a²+b² = c² is for Right angled triange.

  8. #8
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    Originally posted by vsusi
    Now +2 is equalent to -2. If that is equal then 0 = 4 (Am I right)
    No. 2 is NOT equal to -2.
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  9. #9

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    Digital-X-Treme

    I know that +2 cannot be equivalent to -2.
    I would have appreciated if u have given some explanation for ur comment.

    Please read it fully?

    I have written comments for each line. Please specify the error in the code and explain why.

  10. #10
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    Wink Of course not

    Right-angled equilateral triangles are obviously impossible. Hence, 1=1+1 is also impossible. It had to be right-angled to be able to apply Pythagoras, and equilateral for the numbers.

    It's only meant to bypass the dimmer ones.
    Abhishek

  11. #11
    Hyperactive Member DavidHooper's Avatar
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    vsusi, you are not correct and there is no 'bug' in mathematics.

    Here is your argument:
    2 = 2
    Square it
    4 = 4
    Sq Root it.
    I can assume +2 on one side and -2 on another side.
    2 = -2

    Here is the correct argument:
    2 = 2
    4 = 4
    Square Root
    +-2 = +-2

    Your problem is assuming +2 on one side and -2 on another.
    There are 10 types of people in the world - those that understand binary, and those that don't.

  12. #12
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    in math its not seen as just + or just -, but both.....

    +- 2

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    Originally posted by vsusi


    There is no number called +-2 as far as I know. U have to read as + or - 2. Not + and - 2. Only one value.

    In math, regardless of whether +2 or -2 are possible solutions, all possible solutions need to be evaluated, rendering +/-2

    Out

  14. #14
    Fanatic Member simonm's Avatar
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    vsusi

    You are talking rubbish.

    Just because a number has two roots does not mean that those roots are equivillant, does it?

    -2 * -2 = 4
    2 * 2 = 4

    Therefore,

    -2 * -2 = 2 * 2

    => 4 = 4.

    What's contradictory about that?
    Everything I say is either loose interpretation of dubious facts or idle speculation rooted in irrational sentiment.

  15. #15
    Fanatic Member Bonker Gudd's Avatar
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    Angry

    How bored must I have been to have come in here and read this thread

  16. #16

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    SteveCRM & Others

    +-2 is definitely two values. That is how I am proving my equation. ie. +2 and -2. I just said +-2 is not a single value. My argument was a single number cannot have two signs (+ and -)
    But u should assume only one value among the two returned.

    BTW my Windows 98 calculator is showing single value (2). Is that a Microsoft bug then. Microsoft assumes only one value I think.

    Guys I just gave a clue which is similar to what I read some 10 years back. Now I couldn't find that (Mathematics Illusion) book.
    I may lose my bet soon.


    http://www.dictionary.com/search?q=Square%20root

    says

    For example, the square roots of 25 are 5 and -5 because 5 × 5 = 25 and (-5) × (-5) = 25.
    So there are two values.

  17. #17
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    Question Don't be obtuse

    vsusi - I think you are being deliberately obtuse to extend a silly theory.

    A single finite value cannot have two signs, given. But a square root (or lets say the evaluation of the square root function) can yield two answers. I fail to see why you are then arguing that both of those answers (roots) are equivalent.

    Orange trees and apple trees both yield a fruit you can eat.

    That doesn't make an apple an orange.

    Dan

    Outside of a dog, a book is a man's best friend.
    Inside of a dog, it's too dark to read.

  18. #18
    Hyperactive Member DavidHooper's Avatar
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    Orange trees and apple trees both yield a fruit you can eat.

    That doesn't make an apple an orange.
    Chuckle.

    I think this topic is stiched up...
    There are 10 types of people in the world - those that understand binary, and those that don't.

  19. #19
    Fanatic Member alkatran's Avatar
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    ok

    2 does not equal -2
    you're equation is so wrong... 4 squared can eqaul either so
    2² = -2²
    Don't pay attention to this signature, it's contradictory.

  20. #20
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    I almost failed a question on a test like this one. It said what is the square root of 18 (this was primary school maths).

    So I put
    x = 4.24 (2 d.p.)

    I was marked wrong and they said the correct answer was +4.24 and -4.24. I told them to get ****ed since the question didn't ask for two roots, it only asked for the square root, which I was taught to (at the same school) assume that the square root of any positive number is positive.

  21. #21

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    Area of a square is 36 inch2. Find the length of a side.

    Answer is -6 inch and +6 inch. LOL.

  22. #22
    Frenzied Member nishantp's Avatar
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    Originally posted by vsusi
    Area of a square is 36 inch2. Find the length of a side.

    Answer is -6 inch and +6 inch. LOL.
    When relating abstract mathamatical concepts to real life, you have to make certain adjustments, such as discarding negative roots.
    You just proved that sig advertisements work.

  23. #23
    Dreamlax
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    If you measure negative 6 inches would the tape measure go inwards?

  24. #24
    Lively Member mmiill's Avatar
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    lol

    no watch this

    x^2-4=0

    (x-2)(x+2)=0

    x=2 or x=-2

    BUT!!!!!!

    sqrt(4)=+2 and just +2 becouse


    sqrt(x^2)=|x| that is Theorem

    and when u have sqrt((-2)^2)=sqrt(4) =|-2|=+2 and only +2\
    mm

  25. #25
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    vsusi:

    plus OR minus a number....not plus and minus... -2 = -2 or 2 = 2...one or the other

  26. #26
    sql_lall
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    Exclamation What i think you mean is...

    a = 1, b = 1
    a^2 - b^2 = a-b *Diff. of squares
    (a+b)(a-b) = (a-b) *Divide by (a-b)
    a+b = 1
    1+1 = 1
    2=1
    => 2+1 = 1+1, 3=2


    BTW:
    sqrt(x) MEANS +/- sqrt(x). There are two values for sqrt(x)
    =>
    4=4,
    sqrt(4) = sqrt(4)
    THis is as far as you can go.

    "sqrt(4)=+2 and just +2 because sqrt(x^2)=|x| that is Theorem"
    - note that this only applies when only sqrt(x) is written. i.e. if you see just sqrt(x), this implies the positive root.

  27. #27
    Lively Member mmiill's Avatar
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    ?

    u cant devide whit (a-b) becouse a-b=0

    5*0=0
    but 5!=1

    x*0=0 / :0

    =>x=1


    and sqrt(x) can be just +.. there isnt two values!!!!
    mm

  28. #28
    Frenzied Member JungleMan's Avatar
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    Prog_tom can make any equation possible...
    I'm bringing geeky back...

  29. #29
    Hyperactive Member DavidHooper's Avatar
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    Prog_tom can make any equation possible...
    Hehe, good joke.
    There are 10 types of people in the world - those that understand binary, and those that don't.

  30. #30
    Dreamlax
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    I made up a formula to only show half a parabola (by making negative values result in undefinable answers)... the formula was

    y = a * ( (x + |x|) / (x + |x|) ) * ( (x + |x|) / 2 ) ^ 2 + c

    If you notice, the first factor (besides a) won't simplify to 1 if x is negative, since you get 0 / 0. The second factor can just be x but I like it to be complicated.

    I was proud of doing this... until I found out someone already did it before me.

  31. #31
    Dreamlax
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    Re: ?

    Originally posted by mmiill
    u cant devide whit (a-b) becouse a-b=0

    5*0=0
    but 5!=1

    x*0=0 / :0

    =>x=1


    and sqrt(x) can be just +.. there isnt two values!!!!
    Good point! Not to mention well spotted.

  32. #32
    sql_lall
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    Talking THat's the whole point:

    For those who had forgotten early on:
    Steve's right. If the proof resulted in 2 = 3, then there would HAVE to be an error (or some violation) in the math to allow this. I remember seeing a proof on 1+1=1 or something like that, and it involved doing something like:

    1+1 =1
    a+a = b
    ....
    a/(b-a) = something

    and then they continued on with the math using the (b-a) as if it was non-zero
    I was just saying what they were referring to

    Also:
    "and sqrt(x) can be just +.. there isnt two values!!!! "

    But there is two values, i think most people agree that both + and - both are answers.

  33. #33
    Hyperactive Member DavidHooper's Avatar
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    The convention among mathematicians is that:
    sqrt(x) = 4 implies x=2
    x1/2 =4 implies x=+-2
    There are 10 types of people in the world - those that understand binary, and those that don't.

  34. #34
    Dreamlax
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    Hold up, if x ^ 0.5 = 4, shouldn't x = 16? And the answer equal +-4?

  35. #35
    Hyperactive Member DavidHooper's Avatar
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    Sorry! I made a slip of the keyboard. I meant to write:
    sqrt(x) = 4 implies x=16
    x1/2 =4 implies x=+-16

    <Is quite embarrassed!>
    There are 10 types of people in the world - those that understand binary, and those that don't.

  36. #36
    Dreamlax
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    You've done it again! If x is negative, the answer is imaginary!

    Also, I finally found the answer which all mathematicians I spoke to agreed to:

    Code:
    Sqrt ( 16 ) = 4   and not -4...
    The only way to have two answers is to have a question like this:
    Code:
    Solve for x:
    x^2 - 16 = 0

  37. #37
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    The square root of any real number > 0 will always produce two+- real values, as mentioned numerous times in this thread. There's no ifs or buts about it. Its maths. Its just how it is... If people cannot fathom the concept, they should go away and read up on basic algebra, and try to understand further, without coming in here with arguments such as stating 1==2 or the like... </***** over>

    This post is being dragged on...
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  38. #38
    Dreamlax
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    True, for every nth root there are n solutions, including imaginary ones, but if the case was that the square root of a real number equal or above zero is positive or negative, why would the quadratic formula need a +/- sign? Why not just plus... otherwise there would be four solutions, + the positive, - the positive, + the negative, - the negative.

  39. #39
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    I fail to see where you are coming from on the four solution thing... the general form of a quadratic equation is: ax^2 + bx + c

    By completing the square on this general form, we arrive at the quadratic formula, which gives us two solutions:
    Code:
    x = (-b + (b^2-4*a*c)^(1/2) ) / 2 * a
    x = (-b - (b^2-4*a*c)^(1/2) ) / 2 * a
    Digital-X-Treme
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  40. #40
    Hyperactive Member DavidHooper's Avatar
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    Dreamlax, oh dear. How feeble. I'm getting too old for this stuff. Just ignore everything I say ok!

    [Digital-X-Treme],
    If people cannot fathom the concept, they should go away and read up on basic algebra, and try to understand further, without coming in here with arguments such as stating 1==2 or the like... </***** over>
    Pretty funny.
    There are 10 types of people in the world - those that understand binary, and those that don't.

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