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May 21st, 2002, 01:23 PM
#1
Thread Starter
Addicted Member
How to equate 2=3?
Do anyone know how to equate 2 = 3 (using square and square root)?
I knew a long back but I forgot this now.
(Just I was betting with my firend.)
Thanks
Last edited by vsusi; May 21st, 2002 at 01:49 PM.
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May 25th, 2002, 09:28 PM
#2
Frenzied Member
why'd you bet that 2==3???
the equation has an error in it that usually slips by most people...so at first look they make it look like 2==3
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May 25th, 2002, 09:45 PM
#3
Steve's right. If the proof resulted in 2 = 3, then there would HAVE to be an error (or some violation) in the math to allow this. I remember seeing a proof on 1+1=1 or something like that, and it involved doing something like:
1+1 =1
a+a = b
....
a/(b-a) = something
and then they continued on with the math using the (b-a) as if it was non-zero.
Anyhow, I'm super bored, so I thought I'd share that, and one more thing.
If 2 = 3, then it should be that 2 = 3 = 4 = 5 = ... ??
Oh well, back to work. =P
Destined
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May 25th, 2002, 09:57 PM
#4
Frenzied Member
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May 28th, 2002, 12:40 AM
#5
New Member
The proof for 1+1=1 went like this:
Applying a^2 = b^2 + c^2 to an equilateral right-angled triangle, s=1.
Therefore 1^2 = 1^2 + 1^2
1 = 1 + 1
Or something like that...
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May 28th, 2002, 02:39 PM
#6
Frenzied Member
you can't have an equilateral right triangle
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May 28th, 2002, 03:33 PM
#7
Thread Starter
Addicted Member
Friends
I know some of you people were curious about whether the question is right or wrong.
I can tell you that the question is correct using Mathematics bug.
Clue: Assume a number. Let us say 2.
1. Square it. (2²= 4)
2. Now take a square root of 4. (It gives two values. +2 and -2)
3. This is a bug in Math. I used only +2. But now I got -2. Now +2 is equalent to -2. If that is equal then 0 = 4 (Am I right)
This will be a simple proof of 0 = 4
2 = 2
Square it
4 = 4
Sq Root it. I can assume +2 on one side and -2 on another side.
2 = -2
When sending 2 to other side
0 = -2 + (-2)
0 = 4
BTW SteveCRM is correct. Pythagoras says a²+b² = c² is for Right angled triange.
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May 28th, 2002, 04:40 PM
#8
Fanatic Member
Originally posted by vsusi
Now +2 is equalent to -2. If that is equal then 0 = 4 (Am I right)
No. 2 is NOT equal to -2.
Digital-X-Treme
Contact me on MSN Messenger: [email protected]
[VBCODE]Debug.Print Round(((1097) - ((55 ^ 5 + 311 ^ 3 - 11 ^ 3) _
/ (68 ^ 5))) ^ (1 / 7), 13)[/VBCODE]
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May 28th, 2002, 09:26 PM
#9
Thread Starter
Addicted Member
Digital-X-Treme
I know that +2 cannot be equivalent to -2.
I would have appreciated if u have given some explanation for ur comment.
Please read it fully?
I have written comments for each line. Please specify the error in the code and explain why.
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May 29th, 2002, 08:31 AM
#10
New Member
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May 29th, 2002, 01:12 PM
#11
Hyperactive Member
vsusi, you are not correct and there is no 'bug' in mathematics.
Here is your argument:
2 = 2
Square it
4 = 4
Sq Root it.
I can assume +2 on one side and -2 on another side.
2 = -2
Here is the correct argument:
2 = 2
4 = 4
Square Root
+-2 = +-2
Your problem is assuming +2 on one side and -2 on another.
There are 10 types of people in the world - those that understand binary, and those that don't.
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May 29th, 2002, 05:20 PM
#12
Frenzied Member
in math its not seen as just + or just -, but both.....
+- 2
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May 29th, 2002, 07:17 PM
#13
Lively Member
Originally posted by vsusi
There is no number called +-2 as far as I know. U have to read as + or - 2. Not + and - 2. Only one value.
In math, regardless of whether +2 or -2 are possible solutions, all possible solutions need to be evaluated, rendering +/-2
Out
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May 30th, 2002, 05:48 AM
#14
Fanatic Member
vsusi
You are talking rubbish.
Just because a number has two roots does not mean that those roots are equivillant, does it?
-2 * -2 = 4
2 * 2 = 4
Therefore,
-2 * -2 = 2 * 2
=> 4 = 4.
What's contradictory about that?
Everything I say is either loose interpretation of dubious facts or idle speculation rooted in irrational sentiment. 
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May 30th, 2002, 07:50 AM
#15
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May 30th, 2002, 09:11 AM
#16
Thread Starter
Addicted Member
SteveCRM & Others
+-2 is definitely two values. That is how I am proving my equation. ie. +2 and -2. I just said +-2 is not a single value. My argument was a single number cannot have two signs (+ and -)
But u should assume only one value among the two returned.
BTW my Windows 98 calculator is showing single value (2). Is that a Microsoft bug then. Microsoft assumes only one value I think.
Guys I just gave a clue which is similar to what I read some 10 years back. Now I couldn't find that (Mathematics Illusion) book.
I may lose my bet soon.
http://www.dictionary.com/search?q=Square%20root
says
For example, the square roots of 25 are 5 and -5 because 5 × 5 = 25 and (-5) × (-5) = 25.
So there are two values.
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May 30th, 2002, 09:29 AM
#17
Hyperactive Member
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May 30th, 2002, 12:11 PM
#18
Hyperactive Member
Orange trees and apple trees both yield a fruit you can eat.
That doesn't make an apple an orange.
Chuckle.
I think this topic is stiched up...
There are 10 types of people in the world - those that understand binary, and those that don't.
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Jun 2nd, 2002, 10:48 AM
#19
Fanatic Member
ok
2 does not equal -2
you're equation is so wrong... 4 squared can eqaul either so
2² = -2²
Don't pay attention to this signature, it's contradictory.
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Jun 11th, 2002, 11:03 PM
#20
I almost failed a question on a test like this one. It said what is the square root of 18 (this was primary school maths).
So I put
x = 4.24 (2 d.p.)
I was marked wrong and they said the correct answer was +4.24 and -4.24. I told them to get ****ed since the question didn't ask for two roots, it only asked for the square root, which I was taught to (at the same school) assume that the square root of any positive number is positive.
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Jun 12th, 2002, 01:59 PM
#21
Thread Starter
Addicted Member
Area of a square is 36 inch2. Find the length of a side.
Answer is -6 inch and +6 inch. LOL.
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Jun 17th, 2002, 11:41 PM
#22
Frenzied Member
Originally posted by vsusi
Area of a square is 36 inch2. Find the length of a side.
Answer is -6 inch and +6 inch. LOL.
When relating abstract mathamatical concepts to real life, you have to make certain adjustments, such as discarding negative roots.
You just proved that sig advertisements work.
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Jun 18th, 2002, 04:51 AM
#23
If you measure negative 6 inches would the tape measure go inwards?
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Jun 22nd, 2002, 07:08 AM
#24
Lively Member
lol
no watch this
x^2-4=0
(x-2)(x+2)=0
x=2 or x=-2
BUT!!!!!!
sqrt(4)=+2 and just +2 becouse
sqrt(x^2)=|x| that is Theorem
and when u have sqrt((-2)^2)=sqrt(4) =|-2|=+2 and only +2\
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Jun 22nd, 2002, 11:17 AM
#25
Frenzied Member
vsusi:
plus OR minus a number....not plus and minus... -2 = -2 or 2 = 2...one or the other
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Jun 23rd, 2002, 06:02 AM
#26
What i think you mean is...
a = 1, b = 1
a^2 - b^2 = a-b *Diff. of squares
(a+b)(a-b) = (a-b) *Divide by (a-b)
a+b = 1
1+1 = 1
2=1
=> 2+1 = 1+1, 3=2
BTW:
sqrt(x) MEANS +/- sqrt(x). There are two values for sqrt(x)
=>
4=4,
sqrt(4) = sqrt(4)
THis is as far as you can go.
"sqrt(4)=+2 and just +2 because sqrt(x^2)=|x| that is Theorem"
- note that this only applies when only sqrt(x) is written. i.e. if you see just sqrt(x), this implies the positive root.
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Jun 23rd, 2002, 08:43 AM
#27
Lively Member
?
u cant devide whit (a-b) becouse a-b=0
5*0=0
but 5!=1
x*0=0 / :0
=>x=1
and sqrt(x) can be just +.. there isnt two values!!!!
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Jun 23rd, 2002, 02:28 PM
#28
Frenzied Member
Prog_tom can make any equation possible...
I'm bringing geeky back...
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Jun 23rd, 2002, 04:10 PM
#29
Hyperactive Member
Prog_tom can make any equation possible...
Hehe, good joke.
There are 10 types of people in the world - those that understand binary, and those that don't.
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Jun 23rd, 2002, 11:59 PM
#30
I made up a formula to only show half a parabola (by making negative values result in undefinable answers)... the formula was
y = a * ( (x + |x|) / (x + |x|) ) * ( (x + |x|) / 2 ) ^ 2 + c
If you notice, the first factor (besides a) won't simplify to 1 if x is negative, since you get 0 / 0. The second factor can just be x but I like it to be complicated.
I was proud of doing this... until I found out someone already did it before me.
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Jun 24th, 2002, 12:05 AM
#31
Re: ?
Originally posted by mmiill
u cant devide whit (a-b) becouse a-b=0
5*0=0
but 5!=1
x*0=0 / :0
=>x=1
and sqrt(x) can be just +.. there isnt two values!!!!
Good point! Not to mention well spotted.
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Jun 24th, 2002, 04:44 AM
#32
THat's the whole point:
For those who had forgotten early on:
Steve's right. If the proof resulted in 2 = 3, then there would HAVE to be an error (or some violation) in the math to allow this. I remember seeing a proof on 1+1=1 or something like that, and it involved doing something like:
1+1 =1
a+a = b
....
a/(b-a) = something
and then they continued on with the math using the (b-a) as if it was non-zero
I was just saying what they were referring to
Also:
"and sqrt(x) can be just +.. there isnt two values!!!! "
But there is two values, i think most people agree that both + and - both are answers.
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Jun 24th, 2002, 12:54 PM
#33
Hyperactive Member
The convention among mathematicians is that:
sqrt(x) = 4 implies x=2
x1/2 =4 implies x=+-2
There are 10 types of people in the world - those that understand binary, and those that don't.
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Jun 25th, 2002, 12:57 AM
#34
Hold up, if x ^ 0.5 = 4, shouldn't x = 16? And the answer equal +-4?
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Jun 25th, 2002, 12:27 PM
#35
Hyperactive Member
Sorry! I made a slip of the keyboard. I meant to write:
sqrt(x) = 4 implies x=16
x1/2 =4 implies x=+-16
<Is quite embarrassed!>
There are 10 types of people in the world - those that understand binary, and those that don't.
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Jun 25th, 2002, 11:47 PM
#36
You've done it again! If x is negative, the answer is imaginary!
Also, I finally found the answer which all mathematicians I spoke to agreed to:
Code:
Sqrt ( 16 ) = 4 and not -4...
The only way to have two answers is to have a question like this:
Code:
Solve for x:
x^2 - 16 = 0
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Jun 26th, 2002, 05:27 PM
#37
Fanatic Member
The square root of any real number > 0 will always produce two+- real values, as mentioned numerous times in this thread. There's no ifs or buts about it. Its maths. Its just how it is... If people cannot fathom the concept, they should go away and read up on basic algebra, and try to understand further, without coming in here with arguments such as stating 1==2 or the like... </***** over>
This post is being dragged on...
Digital-X-Treme
Contact me on MSN Messenger: [email protected]
[VBCODE]Debug.Print Round(((1097) - ((55 ^ 5 + 311 ^ 3 - 11 ^ 3) _
/ (68 ^ 5))) ^ (1 / 7), 13)[/VBCODE]
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Jun 27th, 2002, 02:24 AM
#38
True, for every nth root there are n solutions, including imaginary ones, but if the case was that the square root of a real number equal or above zero is positive or negative, why would the quadratic formula need a +/- sign? Why not just plus... otherwise there would be four solutions, + the positive, - the positive, + the negative, - the negative.
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Jun 27th, 2002, 12:15 PM
#39
Fanatic Member
I fail to see where you are coming from on the four solution thing... the general form of a quadratic equation is: ax^2 + bx + c
By completing the square on this general form, we arrive at the quadratic formula, which gives us two solutions:
Code:
x = (-b + (b^2-4*a*c)^(1/2) ) / 2 * a
x = (-b - (b^2-4*a*c)^(1/2) ) / 2 * a
Digital-X-Treme
Contact me on MSN Messenger: [email protected]
[VBCODE]Debug.Print Round(((1097) - ((55 ^ 5 + 311 ^ 3 - 11 ^ 3) _
/ (68 ^ 5))) ^ (1 / 7), 13)[/VBCODE]
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Jun 27th, 2002, 12:51 PM
#40
Hyperactive Member
Dreamlax, oh dear. How feeble. I'm getting too old for this stuff. Just ignore everything I say ok!
[Digital-X-Treme],
If people cannot fathom the concept, they should go away and read up on basic algebra, and try to understand further, without coming in here with arguments such as stating 1==2 or the like... </***** over>
Pretty funny.
There are 10 types of people in the world - those that understand binary, and those that don't.
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