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Thread: **SOLVED coefficents of resistance

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    **SOLVED coefficents of resistance

    I have used the stienhar-hart
    1/T = a + b(LN R) + c(Ln R)^3

    to get my coefficents
    0.000484976
    0.000311308
    0.000000490

    Now with this information how do I determine
    what the temperature is ?


    Brad

    The answer is simply plugging in the numbers where 5875 is the resistance of the range 0 to 65535

    1 / 0.000484976 + 0.000311308 * LN(5875) + 0.000000490 *
    (LN(5875)^3) - 273.15 == 12C

    Brad
    Last edited by oddprime; Mar 4th, 2002 at 09:36 AM.
    OddPrime
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